Answer:
7/20
Step-by-step explanation:
given,
2r = 7/10
r= 7/10*1/2
r= 7/20
Answer:
B
Step-by-step explanation:
the side length is equal to sqrt(33)
sqrt(33) = 5.74, closest to 5 3/4
Answer:
The equivalent expression is:
Step-by-step explanation:
We have been given the equation:
Equivalent expression can be computed by solving the expression ai its maximum.
We can factorize the given equation:
By using 
Here, 
Hence, we get the equation below:
Therefore, the equivalent expression is:
Answer:
The radius of the inflated spherical balloon is 45 millimeters.
Step-by-step explanation:
Volume of the spherical water balloon = 121,500 pi cubic millimeters
Let the radius of the balloon = r
Now, Volume of a Sphere = 
⇒
On solving for the value of r, we get:
![r^{3} = \frac{121,500\times 3}{4} = 91125\\ \implies r = \sqrt[3]{91125}](https://tex.z-dn.net/?f=r%5E%7B3%7D%20%20%3D%20%5Cfrac%7B121%2C500%5Ctimes%203%7D%7B4%7D%20%20%20%3D%2091125%5C%5C%20%5Cimplies%20%20r%20%20%3D%20%5Csqrt%5B3%5D%7B91125%7D)
or, r = 45 millimeter
Hence, the radius of the inflated spherical balloon is 45 millimeters.
1. Start with ΔCIJ.
- ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
- the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
- ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.
2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So
m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.
3. Consider ΔCKL.
- ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
- ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
- the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
- ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.
4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So
m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.
5. ΔABC is isosceles, then angles adjacent to the base are congruent:
m∠KBA=m∠JAB → 222°-8x=205°-7x,
7x-8x=205°-222°,
-x=-17°,
x=17°.
Then m∠CAB=m∠CBA=205°-7x=86°.
Answer: 86°.
