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2 years ago

If a rhombus is inside a regular hexagon, what is the size of x

Mathematics

1 answer:

dusya [7]2 years ago

4 0

Answer: x = 60°

Step-by-step explanation:

The rest of the question is the attached figure.

Given: A rhombus inside a regular hexagon, work out the angle x.

As shown

ABCDEF is a regular hexagon.

The regular hexagon have 6 congruent angles, and the sum of the interior angles is 720°

So, the measure of one angle of the regular hexagon = 720/6 = 120°

So, ∠F = ∠BAF = 120°

AFEG is a rhombus.

The rhombus have 2 obtuse angles and 2 acute angles.

∠F is one of the obtuse angles of the rhombus = 120°

∠F and ∠FA G are supplementary angles

So, ∠F + ∠FA G = 180°

∴ ∠FA G = 180° - ∠F = 180 - 120 = 60°

∴ x = ∠GAB = ∠BAF - ∠FA G = 120 - 60 = 60°

So, the measure of the angle x = 60°

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Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

Which is greater the greatest whole number with 4 digits or the least whole number with 5 digits

o-na [289]

The 5 digits hoped I helped

7 0

3 years ago

3. Janet is flying a kite on a string that is 75m long. The kite is 62m above the ground. Estimate the distance between Janet an

konstantin123 [22]

Answer: a) It will be a right triangle with a hypotenuse of 75 and a vertical leg that is 62.
b) The length of the kite string is 75 (given in the problem). However, I believe you are looking for the distance from the spot on the ground beneath the kite to Janet. That is about 42.2 m.

To find the missing distance in the right triangle. You have to use the Pythagorean Theorem. I set it up and solve it below.

a^2 + b^2 = c^2
x^2 + 62^2 = 75^2
x^2 + 3844 = 5625
x^2 = 1781
x = 42.2 (about)

3 0

3 years ago

What is 8,000,000 + 100,000 + 7,000 + 400 + 20 + 4 in standard form?

Alekssandra [29.7K]

Answer:

8107424

Step-by-step explanation:

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3 0

3 years ago

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