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netineya [11]
2 years ago
8

If a rhombus is inside a regular hexagon, what is the size of x

Mathematics
1 answer:
dusya [7]2 years ago
4 0

Answer: x = 60°

Step-by-step explanation:

The rest of the question is the attached figure.

Given: A rhombus inside a regular hexagon, work out the angle x.

As shown

ABCDEF is a regular hexagon.

The regular hexagon have 6 congruent angles, and the sum of the interior angles is 720°

So, the measure of one angle of the regular hexagon = 720/6 = 120°

So, ∠F = ∠BAF = 120°

AFEG is a rhombus.

The rhombus have 2 obtuse angles and 2 acute angles.

∠F is one of the obtuse angles of the rhombus = 120°

∠F and ∠FA G are supplementary angles

So, ∠F + ∠FA G = 180°

∴ ∠FA G = 180° - ∠F = 180 - 120 = 60°

∴ x = ∠GAB = ∠BAF - ∠FA G = 120 - 60 = 60°

So, the measure of the angle x = 60°

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The left and right page numbers of an open book are two consecutive integers whose sum is 335 find these page numbers.
almond37 [142]

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3 0
3 years ago
The school that Imani goes to is selling tickets to the annual dance competition. On the first day of the ticket sales the schoo
Tatiana [17]

Answer:

The adult and the child ticket are both 8 dollars

Step-by-step explanation:

x =adult ticket price

y = child ticket price

I will assume you forget to put that they sold 2 child tickets on the second day

7x+5y=96 and 3x+2y= 40

I will use elimination.  Multiply the first equation by 2 and the second equation by -5 to eliminate y

2(7x+5y)=96*2

14x + 10y = 192

The second equation

-5(3x+2y)= 40*-5

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Add the equations together

14x + 10y = 192

-15x -10y = -200

------------------------

-x = -8

Multiply by -1

x = 8

Now we need to find y

3x+2y= 40

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Subtract 24 from each side

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2y = 16

Divide by 2

2y/2 =16/2

y =8

The adult and the child ticket are both 8 dollars


8 0
3 years ago
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