Yes. When the function f(x) = x3 – 75x + 250 is divided by x + 10, the remainder is zero. Therefore, x + 10 is a factor of f(x) = x3 – 75x + 250.
According to the remainder theorem when f(x) is divided by (x+a) the remainder is f(-a).
In this case,
f(x)=x^3-75x+250
(x+a)=(x+10)
Therefore, the remainder f(-a)=f(-10)
=x^3-75x+250
=(-10)^3-(75*-10)+250
=-1000+750+250
=1000-1000
=0.
The remainder is 0. So, (x+10) is a factor of x^3-75x+250.
To find AB(x) and BC(y), you can do(there are multiple ways you can do this):
tan A = 
tan 60° = or (tan 60°) · 7 = y
tan 60° = 
√3 · 7 = y
7√3 cm = y
sin B = 
sin 30° = or 
sin 30° = 
= 
x = 
x = 14 cm
AB = 14cm
BC = 7√3 cm
The answer is a = 0, b = -5, and c= 39.
<u>Step-by-step explanation</u>:
<u>step 1</u> :
A quadratic equation means that it should have at least one squared term.
<u>step 2</u> :
The standard form is ax² + bx + c = 0.
<u>step 3</u> :
The solution to the quadratic equation is usually written in the form
x = (-b ± √(b2 − 4ac))/(2a)
where a = coefficient of x^2
b = coefficient of x
c = constant term
<u>step 4</u> :
The given equation is -5x +32.
∴ The answer is a = coefficient of x^2 = 0
b = coefficient of x = -5
c = constant term = 39
Same i am sorry need point
Hello!
-6(3x - 2/3)
Distribute the -6
-18x + 4
The answer is D) -18x + 4
Hope this helps!
