X= 1st integer
x+2= 2nd integer
x+4= 3rd integer
Add the integers together
x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer
Substitute x=91 to find 2nd & 3rd integers
2nd Integer
=x+2
=91+2
=93
3rd Integer
=x+4
=91+4
=95
ANSWER: The three test scores are 91, 93 and 95.
Hope this helps! :)
Answer:
B
Step-by-step explanation:
Answer:
Step-by-step explanation:
(a^3 - 2a + 5) - (4a^3 - 5a^2 + a - 2)
=a^3 - 2a + 5 - 4a^3 + 5a^2 - a + 2
= -3a^3 + 5a^2 - 3a + 7
A = -3 B = 39 +6 mo para makuha mo -6 nmn para sa a 3-6 is -3
