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3 years ago

HELP!

Mathematics

2 answers:

ELEN [110]3 years ago

8 0

Answer:

the second option

Step-by-step explanation:

gavmur [86]3 years ago

4 0

It would be 2xa or 2x3

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3 years ago

The sum of three numbers is 41 The second number is 5 times the first. The third number is 14 less than the second. What is the

Elena-2011 [213]

Answer:

the third number is 11

Step-by-step explanation:

the first number is 5 so the second number since its five times the first is 25 and the third being 14 less then the second is 11

so 5+25+11= 41

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3 years ago

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Need help please worth 50 points

Law Incorporation [45]

Here's how you simplify those. The rule for raising an exponent to an exponent is that you multiply them. The rule for dividing exponents with the same base is that you subtract the denomonator from the numerator. So let's simplify the first one, which is actually the most confusing.
$( \frac{ p^{5} }{ p^{-3} q^{-4} } )^{ \frac{1}{4} }$
Multiplying the exponents you get:
$( \frac{ p^{ \frac{5}{4} } }{ p^{- \frac{3}{4} } q^{-1} })$
Subtracting the denominator from the numerator between the common base of p you get this:
$\frac{ p^{ \frac{5}{4}- (-\frac{3}{4}) } }{ q^{-1} }$
Doing that math gives you
$\frac{ p^{2} }{ \frac{1}{q} }$ which equals $\frac{ p^{2} }{1} * \frac{q}{1}$ which is $p^{2}q$ , or the third one down.

The next one:
$( \frac{ p^{2} q^{7} }{ q^{4} } )^{ \frac{1}{2} }$
simplifies to:
$\frac{p* q^{ \frac{7}{2} } }{ q^{2} }$
and subtracting the power of the denominator from the power of the numerator gives you:
$p q^{ \frac{3}{2} }$ , which is the last choice.
$( p^{6}q \frac{3}{2})^{ \frac{1}{3} }$
simplifies to:
$( p^{6* \frac{1}{3} } )( q^{ \frac{3}{2}* \frac{1}{3} })$
which simplifies very nicely to:
$p^{2}q^{ \frac{1}{2} }$ , which is the first choice. The other one is found by process of elimination!

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4 years ago