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alisha [4.7K]
3 years ago
6

Verbal expression for p^4+6r

Mathematics
1 answer:
Goryan [66]3 years ago
4 0
P to the fourth power plus 6r
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Square ABCD was translated using the rule (x, y) → (x – 4, y + 15) to form A'B'C'D'. What are the coordinates of point D in the
charle [14.2K]
X = 9+4 = 13
y = -8 - 15 = - 23

D(13,-23)
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4 years ago
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What is the solution of the system of equations?y = –4x + 10y = –2x – 6(–22, 8)(8, –22)(–2, –2)(–2.67, 20.67)?
forsale [732]
The solution is the second choice:
  (8, -22)

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That is the point on the graph where the line intersect.

5 0
3 years ago
Which expression is equivalent to 4 − (−7)?<br><br> A 7 + 4<br> B 4 − 7<br> C −7 − 4<br> D −4 + 7
ELEN [110]

Answer:

7+4

Step-by-step explanation:

When you are subtracting a negative, you are really adding the number. For example, four minus negative seven is equal to four plus seven.  

4 - (-7) = 4+7

4+7 = 7+4 (By the commutive property of addition)

Let me know if this helps!

3 0
3 years ago
Read 2 more answers
I mark as brainliest ​
Levart [38]

Answer:

C

Step-by-step explanation:

The opposite of any number is its negative number.

5 0
4 years ago
For what value of k, the zeroes of x2 + kx + 12 will differ by 1?
asambeis [7]

Let <em>a</em> and <em>b</em> be the zeroes of <em>x</em>² + <em>kx</em> + 12 such that |<em>a</em> - <em>b</em>| = 1.

By the factor theorem, we can write the quadratic in terms of its zeroes as

<em>x</em>² + <em>kx</em> + 12 = (<em>x</em> - <em>a</em>) (<em>x</em> - <em>b</em>)

Expand the right side and equate the coefficients:

<em>x</em>² + <em>kx</em> + 12 = <em>x</em>² - (<em>a</em> + <em>b</em>) <em>x</em> + <em>ab</em>

Then

<em>a</em> + <em>b</em> = -<em>k</em>

<em>ab</em> = 12

The condition that |<em>a</em> - <em>b</em>| = 1 has two cases, so without loss of generality assume <em>a</em> > <em>b</em>, so that |<em>a</em> - <em>b</em>| = <em>a</em> - <em>b</em>.

Then if <em>a</em> - <em>b</em> = 1, we get <em>b</em> = <em>a</em> - 1. Substitute this into the equations above and solve for <em>k</em> :

<em>a</em> + (<em>a</em> - 1) = -<em>k</em>   →   2<em>a</em> = 1 - <em>k</em>   →   <em>a</em> = (1 - <em>k</em>)/2

<em>a</em> (<em>a</em> - 1) = 12   →   (1 - <em>k</em>)/2 • ((1 - <em>k</em>)/2 - 1) = 12

→   (1 - <em>k</em>)²/4 - (1 - <em>k</em>)/2 = 12

→   (1 - <em>k</em>)² - 2 (1 - <em>k</em>) = 48

→   (1 - 2<em>k</em> + <em>k</em>²) - 2 (1 - <em>k</em>) = 48

→   <em>k</em>² - 1 = 48

→   <em>k</em>² = 49

→   <em>k</em> = ± √(49) = ±7

8 0
3 years ago
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