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VikaD [51]
3 years ago
15

3: Bob has four boards of equal length and wants to be sure that his garden is square. How can he ensure the garden is square by

only measuring length?
A: Arrange the boards so diagonals bisect each other
B: Arrange the boards so that the diagonals are congruent
C: Arrange the boards so that the diagonals are perpendicular
D: Not possible without the ability to measure a right angle


4: Find the measures of the base angles in the isosceles trapezoid shown below.

19x+8 11x+16

A: 49°
B: 46°
C: 38°
D: 27°


7: In the rhombus, m∠1=10x, m∠2=x + y, and m∠3= 5z. Find the values of x, y, and z.


10: Find the values of x and y in the kite shown below.
https://lh6.googleusercontent.com/j5Sk38PdH1gbdH4TFJ2eRGP6qzA0Ym7L3Zgeu6BqgbrcU6YIuBXTt1ThxxdzrBaMEJLr8gK6vg=w413


11: Complete the missing reasons in the proof below.

https://lh5.googleusercontent.com/cWLeD4MjTIcE_FCOeGholJBhW7kmjTbKtsL1o3fmsRMMUlfgHhy2fSjXSWFab2Qg5enzQgO41A=w720
Mathematics
1 answer:
bearhunter [10]3 years ago
7 0
3. I believe the answer is C & A, arrange the boards so that the diagonals bisects and  are perpendicular. A rhombus is a Quadrilateral with all its sides equal to each other. The diagonals of  a rhombus are perpendicular to each other and bisects each other.

4.The corresponding pairs of base angles of a trapezoid add up to 180 degrees, (they are supplementary), While all the angles (the four angles add up to 360 degrees)
Therefore; in this case the two angles are equal
    hence, 19x + 8 = 11x+16    solving for x
                           x = 1
substituting x in either of the expression
The angle = 27 °
 
5. The diagonals of a rhombus bisects each other at right angles; the are perpendicular,
hence,
m∠1= 10x = 90
                 x = 9

m∠2 = x + y =90
but x = 9,
thus, y = 81

m∠3 = 5z= 90
              z =18

10. A kite is a Quadrilateral with two equal sides and the other two sides equal. 
thus, y-4 = 5x+2   and x +22 = 3x +10
solving for x
x+22 = 3x +10
   2x = 12
     x = 6
y-4 = 5x +2
  y-4 = 5(6) +2
      y = 36.

11.a. RHOM is a Quadrilateral with four equal sides
     b. The four sides RH, OH, OM, and RM are equal, They are all congruent
     c   HM and HM is the diagonal, which forms the corresponding sides of triangle MRH and triangle MOH 
      d.  Triangle MRH and triangle MOH are congruent, SSS, and similar to each other.  



                      
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The question is attached at the bottom. PLEASE HELP with detailed explanation!!!
Eva8 [605]
The correct answer are 1 , 3 , 4
8 0
3 years ago
Please help!!!!!!!!!!!!!!!!
riadik2000 [5.3K]
Write f(x) / g(x) = 1 / ((x+1)(x-2)).

It's easy to see that x cannot be -1 and 2;
So all real numbers exclude -1 and 2, which matches the second choice.
6 0
3 years ago
Please help with the working out
nadya68 [22]
I hope this helps you



m=5


(5^2-5.5+9)^2


(25-25+9)^2


9^2


81
5 0
3 years ago
Read 2 more answers
How do u do b??????????
horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

5 0
3 years ago
PLEASE HELP,, MARKING BRAINLIEST!!!
White raven [17]

Answer:

explain what to do

Step-by-step explanation:

3 0
3 years ago
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