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VikaD [51]
3 years ago
15

3: Bob has four boards of equal length and wants to be sure that his garden is square. How can he ensure the garden is square by

only measuring length?
A: Arrange the boards so diagonals bisect each other
B: Arrange the boards so that the diagonals are congruent
C: Arrange the boards so that the diagonals are perpendicular
D: Not possible without the ability to measure a right angle


4: Find the measures of the base angles in the isosceles trapezoid shown below.

19x+8 11x+16

A: 49°
B: 46°
C: 38°
D: 27°


7: In the rhombus, m∠1=10x, m∠2=x + y, and m∠3= 5z. Find the values of x, y, and z.


10: Find the values of x and y in the kite shown below.
https://lh6.googleusercontent.com/j5Sk38PdH1gbdH4TFJ2eRGP6qzA0Ym7L3Zgeu6BqgbrcU6YIuBXTt1ThxxdzrBaMEJLr8gK6vg=w413


11: Complete the missing reasons in the proof below.

https://lh5.googleusercontent.com/cWLeD4MjTIcE_FCOeGholJBhW7kmjTbKtsL1o3fmsRMMUlfgHhy2fSjXSWFab2Qg5enzQgO41A=w720
Mathematics
1 answer:
bearhunter [10]3 years ago
7 0
3. I believe the answer is C & A, arrange the boards so that the diagonals bisects and  are perpendicular. A rhombus is a Quadrilateral with all its sides equal to each other. The diagonals of  a rhombus are perpendicular to each other and bisects each other.

4.The corresponding pairs of base angles of a trapezoid add up to 180 degrees, (they are supplementary), While all the angles (the four angles add up to 360 degrees)
Therefore; in this case the two angles are equal
    hence, 19x + 8 = 11x+16    solving for x
                           x = 1
substituting x in either of the expression
The angle = 27 °
 
5. The diagonals of a rhombus bisects each other at right angles; the are perpendicular,
hence,
m∠1= 10x = 90
                 x = 9

m∠2 = x + y =90
but x = 9,
thus, y = 81

m∠3 = 5z= 90
              z =18

10. A kite is a Quadrilateral with two equal sides and the other two sides equal. 
thus, y-4 = 5x+2   and x +22 = 3x +10
solving for x
x+22 = 3x +10
   2x = 12
     x = 6
y-4 = 5x +2
  y-4 = 5(6) +2
      y = 36.

11.a. RHOM is a Quadrilateral with four equal sides
     b. The four sides RH, OH, OM, and RM are equal, They are all congruent
     c   HM and HM is the diagonal, which forms the corresponding sides of triangle MRH and triangle MOH 
      d.  Triangle MRH and triangle MOH are congruent, SSS, and similar to each other.  



                      
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The volume of a CONE-shaped hole is 75pi ft cubed. If the hole is 9 feet deep, what is the radius of the hole?
Arturiano [62]

Answer:

The radius of hole is 5 feet

Step-by-step explanation:

Depth of conical hole = 9 feet

Let the radius of hole be r

Volume of conical hole =\frac{1}{3} \pi r^2 h

So, Volume of conical hole =\frac{1}{3} \pi \times r^2 \times 9

We are given that volume of a CONE-shaped hole is 75pi ft cubed.

So,\frac{1}{3} \pi \times r^2 \times 9=75 \pi

\frac{1}{3} \times r^2 \times 9=75

r^2=\frac{75 \times 3}{9}

r=\sqrt{\frac{75 \times 3}{9}}

r=5

Hence The radius of hole is 5 feet

6 0
3 years ago
Ritchie got a job at the movie theater. On the first day, he sold 5 adult tickets and 7 children tickets for a total of 104. On
g100num [7]

Answer:

  • adult: $11
  • children: $7

Step-by-step explanation:

The sales on the two days can be expressed using equations that can be solved for ticket prices.

<h3>Setup</h3>

Let x and y represent the prices of adult and children's tickets, respectively. Then the sales revenue for the two days can be expressed in the equations ...

  • 5x +7y = 104
  • 7x +3y = 98

<h3>Solution</h3>

One of the easiest solution methods is to use a graphing calculator. The first attachment shows the prices are $11 for an adult ticket; $7 for children tickets.

Using the matrix functions of a calculator, the augmented matrix of the equation coefficients can be reduced to row-echelon form. This, too, shows the solution to be (adult price, children price) = ($11, $7). See the second attachment. (The solution is the right-most column of the reduced matrix.)

Yet another solution method can use the coefficients from the equations written in general form:

  • 5x +7y -104 = 0
  • 7x +3y -98 = 0

In this form, we define three products of "cross multiplication":

  Δ1 = (5)(3) -(7)(7) = -34

  Δ2 = (7)(-98) -(3)(-104) = -374

  Δ3 = (-104)(7) -(-98)(5) = -238

Using those, we find the variable values to be ...

  x = Δ2/Δ1 = -374/-34 = 11

  y = Δ3/Δ1 = -238/-34 = 7

(adult price, children price) = ($11, $7)

__

You can read more about the cross-multiplication method here:

brainly.com/question/26397343

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1 year ago
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Answer: 113.1

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The mean of Holly's first six math quiz scores was 75%. After taking the seventh quiz, her
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The total of her first six quizzes is 75*6 = 450

Let her seventh score be x
The total of her seven quizzes be 450+x

Then, (450+x)/7 = 77
x = (77*7) - 450 = 89

Her seventh score is 89
x =
3 0
3 years ago
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