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3 years ago

A restaurant has 5 pizza toppings to choose from. How many different 2-topping pizzas are possible?

1 answer:

5 0

10

Because if you do 5•2 you get 10

More in depth explanation:

Though there are 25 possible configurations the question asks for two different toppings together. It also asks for unique combinations. So AB and BA are the same combination in this context. The only unique possibilities are

AB
AC
AD
AE
BC
BD
BE
CD
CE
DE

It is easy to simplify this into 5•2 for this situation. And if the question asked for three toppings you would do 5•3.

However if the question asked for the configurations for two toppings then you would do 5•5 and if it asked for the configurations of 3 toppings you would do 5•5•5

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Suppose a jar contains 16 red marbles and 32 blue marbles. if you reach in the jar and pull out 2 marbles at random, find the pr

valentinak56 [21]

1/6

This is because the probability of pulling a red is 1/3. Multiply that by itself to find the chance of repeating.

5 0

3 years ago

-12 + ( ) = 9 whats the missing number

PilotLPTM [1.2K]

Answer:

The missing number is 21

Step-by-step explanation:

-12 + x = 9

x = 9 + 12

x = 21

7 0

3 years ago

Read 2 more answers

The area of a rectangle is 56 cm. The length is 2 cm more than x and the width is 5 cm less than twice x. Solve for x. Round to

mr Goodwill [35]

I hope this helps you

l=x+2

w=2x-5

(x+2)(2x-5)=56

2x^2-x-10=56

2x^2-x-66=0

2x +11

x -6

(2x+11)(x-6)=0

x=6

6 0

3 years ago

g Disco Fever is randomly found in one half of one percent of the general population. Testing a swatch of clothing for the prese

Marizza181 [45]

Answer:

The probability that the result is positive is P=0.04475=4.475%.

Step-by-step explanation:

We have the events:

D: disease present

ND: disease not present

P: test positive

F: test false

Then, the information we have is:

P(D)=0.005

P(P | D)=0.99

P(P | ND)=0.04

The total amount of positive test are the sum of the positive when the disease is present and the false positives (positive tests when the disease is not present).

$P(P)=P(P | D)*P(D)+P(P | ND)*(1-P(D))\\\\P(P)=0.99*0.005+0.04*0.995\\\\P(P)=0.00495+0.0398=0.04475$

The probability that the result is positive is P=0.04475.

5 0

4 years ago

Triangle PQR has vertices , , and . It is translated according to the rule . What is the y-value of ?

steposvetlana [31]

Answer:

-10 is the correct answer to the given question .

Step-by-step explanation:

Missing information:

Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below

Triangle PQR has vertices $P(-2, 6), \ Q(-8, 4), and\ R(1, -2).$ It is translated according to the rule $(x, y)\ -> \ (x\ - \ 2, y\ - 16)$ . What is the y-value of P'?

Now coming to the solution as already mention in the question

The translated rule is $(x, y)\ -> (x - 2, \ y -16).$

Now calculated the vertices P value according to the rule of translated

$P(-2, 6)\\Now \ apply \ the\ translated\ rule \ in\ P\ vertices\\P(-2, 6)->P1(-2-2,\ 6-16)\\P1->(-4,-10)$

So -10 is the value of y in P vertices .

6 0

4 years ago

Read 2 more answers