Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
M = 5 and x = 4
3(5) - 2(4)
15 - 8 = 7
I hope this helps!
Answer:
The student's GPA is 2.8666.
Step-by-step explanation:
A grade is 4.0, B grade is 3.0, C grade is 2.0. For each credit, add the value of the letter grade. So:
Math, 2 credits, grade A: (4x2=8)
English, 5 credits, grade B: (5x3=15)
Physics, 4 credits, grade B: (4x3=12)
German, 4 credits, grade C: (4x2=8)
The numbers add up to 43, then divide by the number of credits (15) to get:
43/15=GPA of 2.8666.
Answer:8.6 x 104
Step-by-step explanation:
