Question

Solve the compound inequality 10 >= 7 + 3x and 9-4x<=1 . show steps please.

Answer 1

3x + 7 ≤ 10    and    -4x + 9 ≤ 1
      - 7    - 7                    - 9  - 9     Subtract the numbers from each side.
      3x ≤ 3                      -4x ≤ -8    Divide it by the same number.
       3    3                        -4     -4
        x ≤ 1                        x ≥ 2     Find the solution.

Solution Set: {x|2 ≤ x ≤ 1}, [2, 1]

Answer 2

10 >= 7 + 3x                                              -4x+9<=1
-7 >= -7  - subtract 7                                       -9<=-9   - Subtract 9
__________                                               ___________
3 >=3x  - divide by 3                                       -4x<=-8    - divide by -4

x>=1                                                                      x<=2