Solve the compound inequality 10 >= 7 + 3x and 9-4x<=1 . show steps please.

2 answers:

6 0

3x + 7 ≤ 10 and -4x + 9 ≤ 1
- 7 - 7 - 9 - 9 Subtract the numbers from each side.
3x ≤ 3 -4x ≤ -8 Divide it by the same number.
3 3 -4 -4
x ≤ 1 x ≥ 2 Find the solution.

Solution Set: {x|2 ≤ x ≤ 1}, [2, 1]

pav-90 [236]3 years ago

5 0

10 >= 7 + 3x                                              -4x+9<=1
-7 >= -7 - subtract 7                                       -9<=-9   - Subtract 9
__________                                               ___________
3 >=3x - divide by 3                                       -4x<=-8    - divide by -4

x>=1                                                                      x<=2

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