Question

Seven less than negative two times a number is greater than or equal to 41

Answer 1

$Solution, -2n-7\ge \:41\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-24\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-24]\end{bmatrix}$

$Steps:$

$\mathrm{Add\:}7\mathrm{\:to\:both\:sides}, -2n-7+7\ge \:41+7$

$\mathrm{Simplify}, -2n\ge \:48$

$\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}, \left(-2n\right)\left(-1\right)\le \:48\left(-1\right)$

$\mathrm{Simplify}, 2n\le \:-48$

$\mathrm{Divide\:both\:sides\:by\:}2, \frac{2n}{2}\le \frac{-48}{2}$

$\mathrm{Simplify}, n\le \:-24$

The correct answer is $n\le \:-24$

I hope this helps!!!