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2 years ago

Explain the differences (exponents) -6^4 and (-6)^4

Mathematics

1 answer:

wel2 years ago

7 0

Step-by-step explanation:

$- {6}^{4} = - 1296 \\ \\ (- {6})^{4} = 1296$

The product of $-6^4$ is negative whereas the product of $(-6) ^4 is positive.$

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Let XXX and YYY be the following sets: X = \{9, 25\}X={9,25}X, equals, left brace, 9, comma, 25, right brace Y = \{1, 4, 9,16,25

Dmitry_Shevchenko [17]

Answer:

The answer is " $\bold{ \{\phi\}}$ "

Step-by-step explanation:

Given value:

$\ Set\ X = \{9, 25\} \\\\\ Set \ Y = \{ 1,4,9,16,25 \}\\\\Find: \\\\Set (X- Y) \\\\$

When we subtract set X - Y it means, that it will give only, that value which is not available on the set Y.

$\{X-Y\} = \{\phi\}$

5 0

3 years ago

Read 2 more answers

2918+49<br> Which numbers should be used?<br><br> The estimated quotient is?

NNADVOKAT [17]

Answer: Use all numbers to add.

2918+49=2967

Estimated.... 2918+49 ≈ 3050

Hope this helps you out.

6 0

2 years ago

Read 2 more answers

Please help asap!! Is this correct? If not can I please have some help.

Leona [35]

Answer:

Yes, that is correct.

Step-by-step explanation:

3 0

2 years ago

Answer the question in the picture

nekit [7.7K]

Recall the angle sum identities:

$\sin(x+y)=\sin x\cos y+\cos x\sin y$

$\cos(x+y)=\cos x\cos y-\sin x\sin y$

Now,

$\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}$

Divide through numerator and denominator by $\cos x\cos y$ to get

$\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}$

Next, we use the fact that $x,y$ lie in the first quadrant to determine that

$\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2$

$\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}$

So we then have

$\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

$\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1$

Finally,

$\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73$

4 0

2 years ago

What is the 13th term of the geometric sequence with this formula

adell [148]

Answer:

Step-by-step explanation:

You plug in 13 to n-1. to get -2^12. This equates to 4096, and you multiply that by 3

8 0

3 years ago