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mylen [45]
4 years ago
14

Assume that an organism exists in which crossing over does not occur, but that all other processes associated with meiosis occur

normally. Consider how the absence of crossing over would affect the outcome of meiosis. If crossing over did not occur, which of the following statements about meiosis would be true? Select all that apply
Biology
1 answer:
Elenna [48]4 years ago
4 0

Answer:

The question lacks options, the options are:

1. The two daughter cells produced in meiosis I would be identical.

2. There would be less genetic variation among gametes.

3. The two sister chromatids of each replicated chromosome would no longer be identical.

4. The daughter cells of meiosis I would be diploid, but the daughter cells of meiosis II would be haploid.

5. Independent assortment of chromosomes would not occur.

6. The four daughter cells produced in meiosis II would all be different

The answer is 2

Explanation:

Meiosis is a kind of cell division that results in four daughter cells with each having half number of chromosomes as the parent cell. It is the cell division sexually-reproducing organisms undergo to produce gametes. Meiosis is the only cell division in which the process of CROSSING-OVER occurs.

Specifically in the Prophase stage of Meiosis I, equal chromosomal segments are exchanged between homologous chromosomes (similar but non-identical chromosomes received from each parent). This process is called CROSSING-OVER or recombination. In this process, alleles on non-sister chromatids are exchanged in a way to bring about genetic variation in the resulting gametes i.e. gametes with different combinations of alleles.

If crossing-over does not occur, the gametes will contain the exact alleles that segregated from each parent, hence, genetic variation will be reduced.

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What are some similarities and differences between photosynthesis and cellular respiration
Orlov [11]

Answer:

both produce energy

photosynthesis takes glucose molecule but cellular respiration takes it apart

Explanation:

The to process are similar in that they both produce energy, albeit in tow different forms. they are different in that photosynthesis assembles the glucose molecule, while cellular respiration takes it apart : )

6 0
3 years ago
narvez 5. Everyone in Dobby's family has a long nose and they brag that they are from a purebred line. Viola has a stubby nose.
mote1985 [20]

Assuming a single diallelic gene coding for the trait and expressing complete dominance, the phenotypes, genotypes, and probabilities of getting each of them vary according to the parentals' genotypes. See the options below.

---------------------------------

Since I do not have the genotypes from #2, I will provide <em>different potential scenarios </em>for this question.

I advise you to <em>check on them</em> and see <em>which one matches the genotype from #2.</em>

Let us assume a single diallelic gene is coding for the trait and expresses complete dominance.

<h3 /><h3><u>SCENARIO 1</u>  ⇒ long nose is the dominant trait</h3>

Let us say that

  • L is the dominant allele and codes for long nose
  • l is the recessive allele and codes for stubby nose

Since long nose is dominant over stubby nose

  • LL and Ll ⇒ long nose
  • ll ⇒ stubby nose

If Dobby comes from a purebred family and has long nose, his genotype must be LL.

And if Viola has stubbi nose, her genotype must be ll.

<u>Cross 1</u>

Parentals)    LL   x    ll

Gametes)  L    L     l    l

Punnett square)    L       L

                      l      Ll      Ll

                      l      Ll      Ll

F1) Genotype ⇒ 100% heter0zyg0us Ll

     Phenotype ⇒ 100% long-nosed

  • <em>There is 100% chances for a child to have a long nose</em>
  • <em>There is 0% chances for a child to have a stubby nose</em>
  • <em>These children are not purebred</em>

                                             **********

<h3><u>SCENARIO 2</u>  ⇒ Stubby nose is the dominant trait</h3>

Let us say that

  • S is the dominant allele and codes for stubby nose
  • s is the recessive allele and codes for long nose

Since stubby nose is dominant over long nose

  • SS and Ss ⇒ stubby nose
  • ss ⇒ long nose

If Dobby comes from a purebred family and has long nose, his genotype must be ss.

And if Viola has stubbi nose, her genotype must be either SS or Ss.

There are two possible crosses.

<u>Cross 1</u> : Violet is h0m0zyg0us dominant SS

Parentals)    SS   x    ss

Gametes)  S    S     s    s

Punnett square)   S       S

                      s     Ss     Ss

                      s     Ss     Ss

F1) Genotype ⇒ 100% heter0zyg0us Ss

     Phenotype ⇒ 100% stubby-nosed

  • <em>There is 100% chances for a child to have a stubby nose</em>
  • <em>There is 0% chances for a child to have a long nose</em>
  • <em>These children are not purebred</em>

<u>Cross 2</u>: Violet is heter0zyg0us, Ss

Parentals)    Ss   x    ss

Gametes)  S    s     s    s

Punnett square)   S       s

                      s     Ss     ss

                      s     Ss     ss

F1) Genotype ⇒ 50% heter0zyg0us Ss and 50% h0m0zyg0us recessive ss

     Phenotype ⇒ 50% stubby-nosed and 50% long-nosed

  • <em>There is 50% chances for a child to have a stubby nose</em>
  • <em>There is 50% chances for a child to have a long nose</em>
  • <em>These children are not purebred</em>

----------------------------

You can learn more about single gene crosses at

brainly.com/question/12653314?referrer=searchResults

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Definition of thylakoid
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Explanation:

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