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CaHeK987 [17]
3 years ago
10

On a number line what does it mean when it said find the ratio of DH to CE when D=30 H=70 C= 20 and E= 40

Mathematics
1 answer:
puteri [66]3 years ago
7 0

Answer:

Multiply the number and divide by how many numbers were added

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Answer:

Are we supposed to look at a picture of the graph bec if we are I don’t see it

Step-by-step explanation:

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2 years ago
What are the different types of gons. (hexagon, octagon, decagon)
Colt1911 [192]
There could be one more pentagon 

**As far as I know 
3 0
3 years ago
-4 times a number plus 29
kipiarov [429]
-4x+29? I think that's what you're asking.
8 0
3 years ago
10 children equally share 40 almonds <br> How many almonds will 3 children get
pochemuha
The answer is 12

Explanation:

First for this you need to find out how much each child gets

(40 divided by 10)
Each child gets 4 almonds.

If 3 children put their almonds together they will have 12.

(3 times 4)

Brainliest my answer if it helps you out
3 0
2 years ago
Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$
Viktor [21]

When n=0, we have

5^{3^0} + 1 = 5^1 + 1 = 6

3^{0 + 1} = 3^1 = 3

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for n=k, that

3^{k + 1} \mid 5^{3^k} + 1

Now for n=k+1, we have

5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)

so we know the left side is at least divisible by 3^{k+1} by our assumption.

It remains to show that

3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1

which is easily done with Fermat's little theorem. It says

a^p \equiv a \pmod p

where p is prime and a is any integer. Then for any positive integer x,

5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3

Furthermore,

5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3

which goes all the way down to

5^{3^k} \equiv 5 \pmod 3

So, we find that

\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3

QED

5 0
2 years ago
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