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CaHeK987 [17]
3 years ago
10

On a number line what does it mean when it said find the ratio of DH to CE when D=30 H=70 C= 20 and E= 40

Mathematics
1 answer:
puteri [66]3 years ago
7 0

Answer:

Multiply the number and divide by how many numbers were added

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Find the greatest common factor (7) and distribute it so answer is 7(4-x)
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114.9 million U.S. households owned at least one TV set. Of these households, 88% received basic cable. How many households owne
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Find the percentage of the household that didn't receive basic cable
100% - 88% = 12%
<em>This is the percentage of the household that didn't receive basic cable by the household owned TV set.</em>

Now find the number with the percentage
without basic cable = 12% × 114.9 million
without basic cable = 12/100 × 114,900,000
without basic cable = 13,788,000

<em>The number of households that didn't receive basic cable is 13,788,000 or 13,788 million</em>
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3 years ago
Heba's account balance is $29.17. Nour's account balance is $11.99
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Heba has a greater balance and Nour has more debt

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In first grade, Rebecca's school lunch cost $2.50. By seventh grade the cost of lunch increased By 75%
Makovka662 [10]

Answer:

3.25

Step-by-step explanation:

7 0
3 years ago
Certain conditions are set for each race; for example, the age of the horses that could be entered, the gender of the horses tha
Arte-miy333 [17]

Answer/Step-by-step explanation:

a. To construct a stem-and-leaf plot for the given sample data, 7, 13, 28, 12, 16, 23, 13, 49, 18, 11, 9, 27, 36, 18, 15, 11, 32, 22, 19, 21, first, order the data from the least to the greatest.

7, 9, 11, 11, 12, 13, 13, 15, 16, 18, 18, 19, 21, 22, 23, 27, 28, 32, 36, 49

The plot would like the one shown below:

Stem | Leaf

0 | 7, 9

1 | 1, 1, 2, 3, 3, 5, 6, 8, 8, 9

2 | 2, 3, 7, 8

3 | 2, 36

4 | 9

Key:

13 = 1 | 3

b.

i. Mean = (7 + 9 + 11 + 11 + 12 + 13 + 13 + 15 + 16 + 18 + 18 + 19 + 21 + 22 + 23 + 27 + 28 + 32 + 36 + 49)/20

Mean = 400/20

Mean = 20

ii. Median = average of the 10th and 11th data value

Median = (18 + 18)/2 = 36/2

Median = 18

iii. Range = max value - min value

Range = 49 - 7

Range = 42

iv. Standard deviation for sample data is given as s = \sqrt{\frac{1}{N-1} \sum_{i=1}^N (x_i - \overline{x})^2}

Where,

\overline{x} = sample mean = 20

x_i = each value of the sample data

N = total number of values in the sample = 20

Let's solve:

First, calculate (x_i - \overline{x})^2 for each data value:

7 => (7 - 20)² = (-13)² = 169

9 => (9 - 20)² = (-11)² = 121

11 => (11 - 20)² = (-9)² = 81

11 => (11 - 20)² = (-9)² = 81

12 => (12 - 20)² = (-8)² = 64

13 => (13 - 20)² = (-7)² = 49

13 => (13 - 20)² = (-7)² = 49

15 => (15 - 20)² = (-5)² = 25

16 => (16 - 20)² = (-4)² = 16

18 => (18 - 20)² = (-2)² = 4

18 => (18 - 20)² = (-2)² = 4

19 => (19 - 20)² = (-1)² = 1

21 => (21 - 20)² = (1)² = 1

22 => (22 - 20)² = (2)² = 4

23 => (23 - 20)² = (3)² = 9

27 => (27 - 20)² = (7)² = 49

28 => (28 - 20)² = (8)² = 64

32 => (32 - 20)² = (12)² = 144

36 => (36 - 20)² = (16)² = 256

49 => (49 - 20)² = (29)² = 841

Next, calculate \sum_{i=1}^N (x_i - \overline{x})^2 by summing all results gotten above:

= 169 + 121 + 81+ 81 + 64 + 49 + 49 + 25 + 16 + 4 + 4 + 1 + 1 + 4 + 9 + 49 + 64 + 144 + 256 + 841

= 2,032

Next, find \frac{1}{N-1} \sum_{i=1}^N (x_i - \overline{x})^2 by dividing the result you have above by (N - 1):

\frac{2,032}{N - 1} = \frac{2,032}{20 - 1}

\frac{2,032}{19} = 106.947368

Next, calculate s = \sqrt{\frac{1}{N-1} \sum_{i=1}^N (x_i - \overline{x})^2} by finding the square root of the result you have above:

s = \sqrt{106.947}

s = 10.34 (to 2 d.p)

v. Interquartile Range (IQR) = Third Quarter (Q3) - First Quartile (Q1)

Q1 = (12 + 13)/2 = 25/2 = 12.5

Q3 = (23 + 27)/2 = 50/2 = 25

IQR = 25 - 12.5

IQR = 12.5

c. The distribution of the number of horses nominated for each race in the sample is slightly down-skewed. This indicates that most of lower number of horses nominated for each race in the sample chosen are more common. Most of the data values are below the mean value of 20. Also, the median shows the median number of horses selected to be 18, indicating a lower number.

With the distribution having a range value of 42, extreme value such as 49, seem to be an outlier, as it does not reflect the typical number of horses selected in each race, which are mostly lower.

7 0
4 years ago
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