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mojhsa [17]
2 years ago
7

Hi, please help me with the answers for the following questions. For this type of assignment, you make your own algebraic expres

sion that completes the question "requirements"
1) The quotient of a trinomial and monomial in one variable.
2) A practical problem that involves the product or quotient of polynomials.
Mathematics
1 answer:
LenKa [72]2 years ago
3 0

The quotient of a trinomial and monomial can be 9x² +2x + 1 while the product of the polynomials x² + 2x + 1 and 3x² - 1 is 3x⁴  + 6x³ + 2x² - 2x - 1

<h3>The quotient of a trinomial and monomial</h3>

Let the variable be x.

Trinomial are polynomials that have three terms, while monomials have a single term.

Using the above definition, we have:

Trinomial = 9x³ + 2x² + x

Monomial = x

The quotient of the above is represented as:

\frac{9x^3 +2x^2 + x}{x}

Evaluate the quotient

9x² +2x + 1

<h3>The product or quotient of polynomials</h3>

To do this, we make use of the following polynomials:

x² + 2x + 1 and 3x² - 1

The product is represented as:

(x² + 2x + 1) * (3x² - 1)

Expand

3x⁴ - x² + 6x³ - 2x + 3x² - 1

Evaluate the like terms

3x⁴  + 6x³ + 2x² - 2x - 1

Hence, the product of the polynomials x² + 2x + 1 and 3x² - 1 is 3x⁴  + 6x³ + 2x² - 2x - 1

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

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The equation represents a line that passes through(4, 1/3) and has a slope of 3/4 option A; y - 1/3 = 3/4 ( x - 4).

<h3>What is the Point-slope form?</h3>

The equation of the straight line has its slope and given point.

If we have a non-vertical line that passes through any point(x1, y1) has gradient m. then general point (x, y) must satisfy the equation

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we know that            

The equation of the line into point-slope form is equal to                        

y-y₁ = m(x-x₁)

             

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