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mojhsa [17]
1 year ago
7

Hi, please help me with the answers for the following questions. For this type of assignment, you make your own algebraic expres

sion that completes the question "requirements"
1) The quotient of a trinomial and monomial in one variable.
2) A practical problem that involves the product or quotient of polynomials.
Mathematics
1 answer:
LenKa [72]1 year ago
3 0

The quotient of a trinomial and monomial can be 9x² +2x + 1 while the product of the polynomials x² + 2x + 1 and 3x² - 1 is 3x⁴  + 6x³ + 2x² - 2x - 1

<h3>The quotient of a trinomial and monomial</h3>

Let the variable be x.

Trinomial are polynomials that have three terms, while monomials have a single term.

Using the above definition, we have:

Trinomial = 9x³ + 2x² + x

Monomial = x

The quotient of the above is represented as:

\frac{9x^3 +2x^2 + x}{x}

Evaluate the quotient

9x² +2x + 1

<h3>The product or quotient of polynomials</h3>

To do this, we make use of the following polynomials:

x² + 2x + 1 and 3x² - 1

The product is represented as:

(x² + 2x + 1) * (3x² - 1)

Expand

3x⁴ - x² + 6x³ - 2x + 3x² - 1

Evaluate the like terms

3x⁴  + 6x³ + 2x² - 2x - 1

Hence, the product of the polynomials x² + 2x + 1 and 3x² - 1 is 3x⁴  + 6x³ + 2x² - 2x - 1

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

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When the football is 81 feet high, it will be √  3 / 8 seconds

<h3>Function</h3>

Function relates input to output. Therefore,

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Therefore,

t = number of seconds

h(t) = - 16t² + 75

h(t) = 81 ft

Therefore,

81 = - 16t² + 75

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- 16t²  = 6

divide both sides by -16

t² = 6 / -16

t² = - 3 / 8

square root both sides

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learn more on function here: brainly.com/question/4418459

6 0
2 years ago
A cone has a diameter of 18 units and height of 8 units. What is its volume?
sveta [45]
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The volume of any cone is      <span><span>V = (1/3) · (pi) · (radius)² · (height) </span>
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-- Take that formula for the volume of any cone.
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A ship of unknown heightis sighted from a lighthouse. From the top of the lighthouse, the angle of depression to the top of the
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Answer:

           

Step-by-step explanation:

From the given information, consider DB=x be the height of the ship, BC= 50 m, then DE=50 m.

Now, From ΔABC,

\frac{AC}{BC}=tan45^{\circ}

⇒AC=50 m

Also, from ΔADE, DE=50 m, we have

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⇒\frac{AE}{50}=\frac{1}{\sqrt{3}}

AE=\frac{50}{\sqrt{3}}

Now, AC=AE+EC

⇒50=\frac{50}{\sqrt{3}}+EC

⇒EC=50-\frac{50}{\sqrt{3}}

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Thus,the height of the ship= 21.14 meters.

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