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sasho [114]
3 years ago
7

Somebody please answers these!!!!

Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer: 1: B

Step-by-step explanation:

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d is the answerStep-by-step explanation:

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Use the graph of the polynomial function to find the factored form of the related polynomial. Assume it has no constant factor.
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Answer: C

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A soft drink company fills two-liter bottles on several different lines of production equipment. The fill volumes are normally d
pshichka [43]

Answer:

a) There is a 15.62% probability that a randomly selected two-liter bottle would contain between 1.95 and 2.03 liters.

b) The score is X = 2.062

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that

The fill volumes are normally distributed with a mean of 1.97 liters and a variance of 0.04 (liter)2 (i.e. a standard deviation of 0.2 liter). This means that \mu = 1.97, \sigma = 0.2.

a. Find the probability that a randomly selected two-liter bottle would contain between 1.95 and 2.03 liters.

This is the pvalue of the Z score of X = 2.03 subtracted by the pvalue of the Z score of X = 1.95.

X = 2.03

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.03 - 1.97}{0.2}

Z = 0.3

Z = 0.3 has a pvalue of 0.6179

X = 1.95

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.95 - 1.97}{0.2}

Z = -0.1

Z = -0.1 has a pvalue of 0.4617.

This means that there is a 0.6179-0.4617 = 0.1562 = 15.62% probability that a randomly selected two-liter bottle would contain between 1.95 and 2.03 liters.

b. If X is the fill volume of a randomly selected two-liter bottle, find the value of x for which P(X > x) = 0.3228.

This is the value of X when Z has a pvalue of 1-0.3228 = 0.6772. This is when Z = 0.46. So:

Z = \frac{X - \mu}{\sigma}

0.46 = \frac{X - 1.97}{0.2}

X - 1.97 = 0.46*0.2

X = 2.062

The score is X = 2.062

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4 years ago
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Answer:

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Step-by-step explanation:

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