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sasho [114]
3 years ago
7

Somebody please answers these!!!!

Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer: 1: B

Step-by-step explanation:

You might be interested in
Whats the elasped time between 9:00 and 1:30
Tasya [4]

Answer:

4 hours and 30 minutes

Step-by-step explanation:

I'll assume you have a basic knowledge of time and know the sequence. So all you do is count to 1:00 and see how many steps you took. In this case 4, but then you have 30 minutes left. Add that to the 4 hours, and you have a total of 4 hours and 30 minutes of elapsed time.

Hope this helps :)

7 0
3 years ago
Multiply me by 4 then subtract 13 if you divide me by 3 and add 17 you get 22
8_murik_8 [283]
You have to do the opposite

22-17=5
5x3=15
15+13=28
28/4=7

The answer is 7. You can check this by doing what it says and if it makes 22, it’s correct. (I’ve already checked it) :)
6 0
3 years ago
HELP ASAP FOR BRAINLIEST!!
Diano4ka-milaya [45]

Answer:

Not equivalent

Step-by-step explanation:

The three would also be distributed to z making the correct equivalent expression 15+3z

8 0
3 years ago
Help me plzzzzzz........
Tanya [424]

Answer:

Step 1

Step-by-step explanation:

You should isolate the variable, not try to get rid of it. Also, you have to divide both sides by the same number or variable(can't divide one side by a and the other side by 7- it has to be the same).

4 0
3 years ago
Read 2 more answers
Evaluate the difference quotient for the given function. Simplify your answer.
nasty-shy [4]

I suppose you mean

f(x) = \dfrac{x+5}{x+1}

Then

f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2

and the difference quotient is

\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with

\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}

4 0
3 years ago
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