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anyanavicka [17]
4 years ago
5

Sixity five is a number cubed increased by seven

Mathematics
1 answer:
Olenka [21]4 years ago
5 0

Answer:

65=x^3+7

Step-by-step explanation:

65=x^3+7

I am not sure if I am supposed to solve this but first you would subtract 7 from both sides and get 58=x^3 and then take the cube root of both sides which is x=3.87...

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211 times 9=<—round the answer.
Yuki888 [10]

Answer:

211 × 9 is 1899 so rounding to nearest thousands would be 2000

3 0
3 years ago
What are the common factors of 24, 64, and 88
Zarrin [17]
1,2,4 & 8 

12*2<span> = 24</span>
32*2<span> = 64 </span>
44*2<span> = 88 </span>
 
6*4 = 24 
16*4 = 24

<span>etc. </span>
3 0
3 years ago
Read 2 more answers
A regular pentagon has side lengths of 10 cm and an
Fittoniya [83]

Answer: 172 square centimeters.

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a pentagon (A) = 1/2× 5s × a

Where:

s : side of the pentagon

a: apothem

Replacing with the values given and solving for A (area):

A =1/2 x (5 x10) x 6.88

A = 172 square centimeters.

Feel free to ask for more if needed or if you did not understand something.

7 0
3 years ago
What’s the 5th term is 2,14,98
iragen [17]

\bold{\huge{\orange{\underline{ Solution }}}}

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

  • \sf{ 2 , 14 ,.... 98 }
  • <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

  • \sf{a1\: or \:1st\: term = 2 }
  • \sf{a2 \:or \:2nd\: term = 14 }
  • \sf{an \:or\: last\: term = 98}

<u>Here</u><u>, </u>

Common difference of an AP

\sf{ a2 - a1 }

\sf{ = 14 - 2}

\sf{ = 12}

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

\sf{an = a1 + ( n - 1 )d}

\sf{a5 = 2 + ( 5 - 1 )12}

\sf{a5 = 2 + 4 × 12}

\sf{a5 = 2 + 48}

\sf{\red{a5 = 50}}

Hence, The 5th term of given AP is 50

4 0
3 years ago
What is 99 divided bye 100
WINSTONCH [101]

Answer:

= 0.99

Step-by-step explanation:

6 0
4 years ago
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