Using the concept of an one-to-one function, it will be one-to-one for c = 13.
<h3>What is an one-to-one function?</h3>
A function is said to be one-to-one if each output is mapped to only one input.
In this problem, outputs 2, 5 and 11 have already been matched to inputs 1, 3 and 5, respectively, hence the output for input 6 has to be c = 13 for a one-to-one function.
More can be learned about one-to-one functions at brainly.com/question/10853542
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The inequality that is true is 7π > 21
<h3>How to determine the inequality that is true?</h3>
To do this, we simply test the given inequalities (starting from the first)
The first inequality is represented as
7π > 21
Divide both sides of the inequality by 7
So, we have:
7π/7 > 21/7
Evaluate the quotient of 21 and 7
So, we have:
7π/7 > 3
Evaluate the quotient of 7π and 7
So, we have:
π > 3
The above inequality is true.
This is so because π = 3.14 and 3.14 > 3
Hence, the inequality that is true is 7π > 21
Read more about inequality at
brainly.com/question/24372553
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Answer:
maybe 42
Step-by-step explanation:
by the way am bad in maths but still
1.so what you are going to do it add up all the sides but not just in any order you are going to add up the like terms so 2/3x+1/3x+2/3x+1/3x that adds up to be 2x and the add up 10+5+10+5 which equals 30 so there you go. Your perimeter= 2x+30
2. -2/3 has a repeating decimal
This should be A. Hope this helps!
