F=ir^t
139=134r^10
139/134=r^10
r=(139/134)^(1/10) then:
f=134(139/134)^(t/10) so in 2014, t=24 so
f=134(139/134)^(2.4)
f≈146 million (to nearest million)
Some will say that you have to use the exponential function, but it really gives you the same answer...even for continuous compounding :)...
A=Pe^(kt)
139=134e^(10k)
139/134=e^(10k)
ln(139/134)=10k
k=ln(139/134)/10 so
A=134e^(t*ln(139/134)/10) when t=24
A=134e^(2.4*ln(139/134))
A≈146 million (to nearest million)
The only real reason or advantage to using A=Pe^(kt) is when you start getting into differential equations...
Answer:
64
Step-by-step explanation:
Since 64 is a multiple of itself and of all the other numbers, the answer is 64.
Answer:
b
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
1. You have the following points given in the problem above:
A<span>(-2,3), B(9,3), C(5,6) and D(2,6)
2. When you plot them, you obtain the figure shown in the graph attached.
3. Therefore, as you can see,
the answer is: the figure is a trapezoid, which is define as a quadrilateral with two parallel sides.</span>
2 and 3 are prime numbers, so it means that the greatest common factor is:
G.C.M(2;3)=2*3=6