Step-by-step explanation:
You have to do first and second derivatives :
y = a sin 3x + b cos 3x
dy/dx = 3a cos 3x - 3b sin 3x
d²y/dx² = - 9a sin 3x - 9b cos 3x
Next, you have to compare it :
let d²y/dx² = ky,
-9a sin 3x - 9b cos 3x = k(a sin 3x + b cos 3x)
-9(a sin 3x + b cos 3x) = k(a sin 3x + b cos 3x)
Therefore, k is equals to 9.
Answer:
x=-4 x=-2
Step-by-step explanation:
x² + 6x + 8 = 0
x² +2x+4x + 8 = 0
x(x+2)+4(x+2)=0
(x+4)(x+2)
x=-4 x=-2
The first thing I'll do is solve "5y = 2x + 20" for "<span>y=</span>", so that I can find my reference slope:
y = (2/5)x + 4;
So the reference slope from the reference line is <span>m = 2/5;</span>.
Now I need to find two new slopes, and use them with the point they've given me; namely, with the point (-1, 3). They want me to find the line through (4, –1) that is parallel to 5y = 2x + 20; that is, through the given point, they want me to find a line that has the same slope as the reference line.
Since a parallel line has an identical slope, then the parallel line through (-1, 3) will have slope <span>m = 2/5</span>. Now I have a point and a slope! So I'll use the point-slope form to find the line: y - 3 = (2/5)( x + 1);
Finally, y = (2/5)x + 17/5;
Answer:
The actual distance is 11.7km
Step-by-step explanation:
2cm = 1km
1cm = 0.5km
23.4cm = ?
23.4 × 0.5 = 11.7km
(Correct me if i am wrong)
Answer:
p = -5
Step-by-step explanation:
11p-3p = 8p
-47+ 7 = -40
8p = -40
-40/8 = -5
