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Scrat [10]
3 years ago
8

The line y = 5x/3 + b goes through the point (7, –1). What is the value of b?

Mathematics
1 answer:
mars1129 [50]3 years ago
3 0

Answer:

y=\frac{5}{3} x-\frac{38}{3}

the value of b is -38/3

Step-by-step explanation:

y=\frac{5}{3} x+b goes through the point (7,-1)

we need to find out b for the given equation using (7,-1)

Plug in 7 for x  and -1 for y

y=\frac{5}{3} x+b

-1=\frac{5}{3} (7)+b

-1=\frac{35}{3}+b

subtract 35/3 from both sides

-1 -\frac{35}{3} =b

\frac{-38}{3} =b

Replace it in the original equation

y=\frac{5}{3} x-\frac{38}{3}

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\bf (\stackrel{a}{1}~,~\stackrel{b}{-1})\qquad \impliedby \textit{let's find the hypotenuse} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c = \sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{1^2+(-1)^2}\implies c=\sqrt{2} \\\\[-0.35em] ~\dotfill

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Read 2 more answers
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