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Scrat [10]
2 years ago
8

The line y = 5x/3 + b goes through the point (7, –1). What is the value of b?

Mathematics
1 answer:
mars1129 [50]2 years ago
3 0

Answer:

y=\frac{5}{3} x-\frac{38}{3}

the value of b is -38/3

Step-by-step explanation:

y=\frac{5}{3} x+b goes through the point (7,-1)

we need to find out b for the given equation using (7,-1)

Plug in 7 for x  and -1 for y

y=\frac{5}{3} x+b

-1=\frac{5}{3} (7)+b

-1=\frac{35}{3}+b

subtract 35/3 from both sides

-1 -\frac{35}{3} =b

\frac{-38}{3} =b

Replace it in the original equation

y=\frac{5}{3} x-\frac{38}{3}

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What is the lowest value in the set of data represented by the following box-and-whisker plot?
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D.11.5 because when you bring the line and the dot it is 11.5
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3 years ago
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A hardware store rents vacuum cleaners that customers may use for part or all of a day, up to 12 hours, before returning. The st
jek_recluse [69]

The flat fee that the store charges is $14 and the cost for 7 hours is $56

A linear equation is on the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

let f for the total rental cost of a vacuum cleaner for x hours

Using the points (1, 20) and (3, 32) from the table:

f-f_1=\frac{f_2-f_1}{x_2-x_1} (x-x_1)\\\\f-20=\frac{32-20}{3-1} (x-1)\\\\f(x)=6x+14

The flat fee that the store charges is $14

The reasonable domain is 1 ≤ x ≤ 12

The cost for 7 hours is:

f(7) = 6(7) + 14 = 46

Find out more on linear equation at: brainly.com/question/14323743

4 0
2 years ago
Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,
Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁,  of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}

Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times  (720-576)\times  (720 - 672)}

Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times  144 \times  48} = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}

The semi-perimeter, s₂,  of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times  (690 -228)\times  (690 - 480)}

Area\, of \, \Delta ACD = \sqrt{690 \times 18\times  462\times  210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

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Rina8888 [55]

Answer:

The final temperature was 9 degrees.

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You can first multiply 13x2, 7x2, and 9x2. Then you subtract 26 and 18 from 34. then add 14

4 0
2 years ago
F(x) = 3x-7 and g(x) = -2x-6. Find (f o g)(4)
USPshnik [31]
<span>(f o g)(4) = f(g(4))
so
g(4) = </span><span>-2(4) -6 = -14
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answer
</span><span> (f o g)(4) = -49</span>
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