Answer is in the screenshot.
The measurement of EF is EF=5.9
Answer:
does anybody?
Step-by-step explanation:
attach work
Total number of ways to make a pair:
The first player can be any one of 7 . For each of those . . .
The opponent can be any one of the remaining 6 .
Total ways to make a pair = 7 x 6 = 42 ways .
BUT ... every pair can be made in two ways ... A vs B or B vs A .
So 42 'ways' make only (42/2) = 21 different pairs.
If every pair plays 2 matches, then (21 x 2) = <em><u>42 total matches</u></em> will be played.
Now, is that an elegant solution or what !
Answer:
number 1 + number 2 + number 3 = 15
Number 1 = x + 12
Number 2 = x - 12
Number 3 = x
(x + 12) + (x - 12) + x = 15
x + 12 + x - 12 + x = 15
x + x + x +12 -12 = 15
3x = 15
x = 15/3 = 5
Check:
Number 1 = 17
Number 2 = 5 -12 = -7
Number = 5
number 1 + number 2 + number 3 = 15
17 + (-7) + 5 = 15
10 + 5 = 15
15 = 15
Answer is 5
Step-by-step explanation: