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Ivenika [448]
3 years ago
8

HELP

Mathematics
2 answers:
iris [78.8K]3 years ago
6 0

Answer:

D x≥4

Step-by-step explanation:

−7 ≥ 13−5x

5x ≥ 20

x ≥ 4

Otrada [13]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Given

- 7 ≥ 13 - 5x ( add 5x to both sides )

5x - 7 ≥ 13 ( add 7 to both sides )

5x ≥ 20 ( divide both sides by 5 )

x ≥ 4 → D

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Write in simplest form:<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24a%5E%7B10%7Db%5E%7B6%7D%7D" id="TexFormula1" ti
Charra [1.4K]

Answer:

2a^3b^2\sqrt[3]{3a}

Step-by-step explanation:

Use the following rules for exponents:

a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x

Simplify 24. Find two factors of 24, one of which should be a perfect cube:

8*3=24\\\\2^3=8

Insert:

\sqrt[3]{2^3*3a^{10}b^6}

Now split the exponents. Split 10 into as many 3's as possible:

10=3+3+3+1

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}

Split 6 into as many 3's as possible:

6=3+3

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}

Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):

2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}

Simplify:

2a^3b^2\sqrt[3]{3a}

:Done

6 0
3 years ago
12 to 15 pls guys thx
Schach [20]
Yes she will have have money to buy all the toppings
8 0
3 years ago
Suppose a pack of candy bars has 4 bars. Each bar weighs 5.88 ounces. How much does the pack weigh?
frutty [35]
The answer is 23.52 the keyword is each so you multiply.
7 0
3 years ago
Read 2 more answers
I need Serious help here!
marishachu [46]

Answer:

Step-by-step explanation:

0.5

7 0
2 years ago
Read 2 more answers
3-6n+3n=-3+4-4n can somebody help me?
ElenaW [278]
Anwser : n = -2
Combine Like Terms
Add 4n to both sides
Subtract 3 from both sides
A = n= -2
8 0
3 years ago
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