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Ipatiy [6.2K]
3 years ago
11

Conjugation is a very effective process for spreading antibiotic resistance among diverse bacterial populations such as those fo

und in the mammalian gut. Which statement best explains this observation?
A) Conjugative plasmids can be transferred to a bacteriophage.
B) Two different species of bacteria can share DNA, including antibiotic-resistance genes, during conjugation.
C) Conjugation is the only source of genetic variation in bacterial cells.
D) Conjugative plasmids cause a bacterial cell to reproduce more quickly, which increases the rate of evolution and the appearance of antibiotic resistance.
Biology
1 answer:
ololo11 [35]3 years ago
7 0

Answer:

B) Two different species of bacteria can share DNA, including antibiotic-resistance genes, during conjugation.

Explanation:

Conjugation is a process by which bacteria can exchange their genetic material between them. So through conjugation, the antibiotic-resistant gene coded by plasmid can be transferred through sex pilus to another bacteria.

So due to conjugation two different species of bacteria can share DNA which can include antibiotic-resistant genes. Therefore, through conjugation genetic variation and evolution are favored in bacteria. So due to this reason conjugation is a very important process in bacteria to spread antibiotic-resistant genes.

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A farmer wants to know if adding antibiotics to cow feed will fatten them up. He takes two groups of 25 cows each. One group is
galina1969 [7]

Answer:

The correct answer is-

Hypothesis: Antibiotics cause weight gain in cows.

Independent Variable: Antibiotic pill

Dependent Variable: Weight of cow

Control Group: a group of cows gets a placebo pill

Experimental Group: a group of cows gets an antibiotic pill

Explanation:

The Independent variable is the variable that causes the response from the dependent variable or affects the dependent variable in this study the antibiotic pill affects the weight of cows so The independent variable is an antibiotic pill and the dependent variable is the weight of cows.

The control group is the group of subjects that did not get the treatment in a scientific study in the case of this study group of cows that receives the placebo pill is the control group and the experiment group is subjects that receive the treatment which is a group with the antibiotic pill.

4 0
3 years ago
if we use a cscl gradient to test the density of various nucleic acids, both rna and dna-rna hybrids are more density than just
Wewaii [24]

RNA and DNA-RNA hybrids are more dense than simply DNA if the density of different nucleic acids is tested using a CsCl gradient.

The primary technique employed in molecular biology is the extraction of DNA, RNA, and protein. Scientists can separate materials according to size, shape, and density by using density gradient centrifugation. Isopycnic centrifugation, a sort of density gradient centrifugation that Meselson and Stahl developed, employed a cesium chloride solution to separate DNA molecules solely on the basis of density. Because DNA has hydrogen bonds between its strands, which makes it less dense than RNA, RNA has a far larger density than DNA. RNA can be obtained at the test tube's bottom using a CsCl density gradient and high centrifugation, whereas DNA can be recovered in the middle layer.

To learn more about nucleic acids click here brainly.com/question/11309892

#SPJ4

6 0
1 year ago
In a species of bird, the allele for the striped trait is recessive to the allele for the speckled trait. Suppose that a coastal
mylen [45]

Answer:

The answer is "0.42"

Explanation:

Please find the complete question in the attached file.

Coastal community striped allele intensity = q = 0.62

Landlocked community, strip intensity allele=q'=0.40

Its eliminated allele frequency for movement = q"=0.42 \ in \ indoorscommunity And now in the sturdy vineyard optimum communities, genotype frequency of stripped characteristic (heterozygous device) in coasts=q_2=0.39

Heritable (striped) allele frecency:

\to q=\sqrt{q_2}

      =\sqrt{0.39} \\\\ =0.624 \\\\ =0.62

(round up to the closest cent) is therefore the only frequency of coastal people.

The genome of pulling function in host population= q'_2=0.16 Heterozygous feature regularly.

Therefore the inland community rate of recessed (striped), allele rate:

\to q'= \sqrt{q'_{2}}= \sqrt{0.16}=0.40

Following migration;

Its percentage of coastal migrants:

m=10\% \\\\

   = \frac{10}{100} \\\\= 0.1

Coastal population Non-immigrant percentage of coastal residents:

=1- m\\\\=1-0.1\\\\ =0.9

Stripping coastal community of allele rate after immigration:

(q")=\text{(stripping of migrant only freq)}\times (m)+\text{(stripping allele baud rate for non-immigrants)} \times ( 1-m)

       = [q \times m]+[[q' \times(1-m)]\\\\=(0.62 \times 0.1)+(0.40 \times 0.9)\\\\=0.062+ 0.36\\\\=0.422\\\\=0.42

8 0
3 years ago
The knob like structures present on the hyphae are referred as (1)
julsineya [31]

\huge\star{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}\star

[b] The sporangia are knob-like structures.

They are present at the top of the thread-like structures called hyphae.

They are dispersive, i.e. they are scattered by rain, wind or insects.

4 0
2 years ago
What force drives the movement of tectonic plates?
mixer [17]
I think it’s C....
I know for sure that it isn’t B or D for sure
3 0
3 years ago
Read 2 more answers
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