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3 years ago

Factor the equation 12x4 - 27x3 + 6x2

Mathematics

1 answer:

Sindrei [870]3 years ago

7 0

3x^2(x-2)(4x-1) this is correct........

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A restaurant charges $5.00 for a slice of pizza that is 1/3 of a pizza and $4.50 for a slice that is 1/5 of a pizza. One day the

katrin [286]

Answer:

Step-by-step explanation:

Given that:

Price of whole pizza (A) = 5 × 3 = $15
Price of whole pizza (B) = 4.50 × 5 = $22.50

They make 8 whole pizzas.

Therefore

Thirds (A) = 15 × 8 = $120
Fifths (B) = 22.50 × 8 = $180

They'll make more money if they slice it into fifths.

180 - 120 = $60

Because if they slice it into thirds, total profit will be $60 less

____________________

#IndonesianPride - kexcvi

7 0

2 years ago

Needing help with this!

Sonbull [250]

assuming the scale is by 1,

a) the slope is rise/run so it rises 3 units and moves 4 units right therefore the slope is 3/4

b) the y intercept is where the line crosses the y axis so by looking at the graph you can tell that the y int is 1

c) and the equation is made up of the slope and the y intercept: y= 3/4x + 1

6 0

3 years ago

Write only vertical translation

Free_Kalibri [48]

Answer:

I hope this helps

Ex: vertical translation |x+5|-2 the graph will shift down 2 units. Or the same as (x+5)+2 in this case the graph will shift up 2 units.

Horizontal translation |x+5|-2 the graph will shift to the left 5 units. Or same as (x-5)-2 in this case the graph will shift over to the right 5 units.

Step-by-step explanation:

Vertical translation is when a graph is being shifted up or down.

Horizontal translation is when a graph is being shifted over left or right.

5 0

3 years ago

What is 7/28 in simplest form?

ElenaW [278]

You find a common greatest factor, which in this case is 7. 1/4 is your answer.

8 0

3 years ago

Read 2 more answers

Find the value of the following expression: (2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ 5 to the power of negative 2 over 2 to the power of 3, whol

koban [17]

Answer:

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

Step-by-step explanation:

$\left(2^8\cdot5^{-5}\cdot19^0\right)^{-2}\cdot\left(\dfrac{5^{-2}}{2^3}\right)^4\cdot228\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\ \text{and}\ a^0=1\ \text{and}\ (a^n)^m=a^{nm}\\\\=\left(2^8\cdot\dfrac{1}{5^5}\cdot1\right)^{-2}\cdot\left(\dfrac{\frac{1}{5^2}}{2^3}\right)^4\cdot228=\left(\dfrac{2^8}{5^5}\right)^{-2}\cdot\left(\dfrac{1}{2^35^2}\right)^4\cdot228$

$=\dfrac{(2^8)^{-2}}{(5^5)^{-2}}\cdot\dfrac{1^4}{(2^3)^4(5^2)^4}\cdot228=\dfrac{2^{-16}}{5^{-10}}\cdot\dfrac{1}{2^{12}5^8}\cdot228\\\\\text{use}\ a^n=\dfrac{1}{a^{-n}}\to\dfrac{1}{a^n}=a^{-n}\\\\=2^{-16}\cdot5^{10}\cdot2^{-12}\cdot5^{-8}\cdot228\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2^{-16+(-12)}\cdot5^{10+(-8)}\cdot228=2^{-28}\cdot5^2\cdot228\\\\=2^{-28}\cdot5^2\cdot4\cdot57=2^{-28}\cdot5^2\cdot2^2\cdot57=2^{-28+2}\cdot5^2\cdot57\\\\=2^{-26}\cdot5^2\cdot57=\dfrac{5^2\cdot57}{2^{26}}$

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

4 0

2 years ago