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3 years ago

Combine Like Terms and Evaluate

Mathematics

2 answers:

rosijanka [135]3 years ago

6 0

Answer:

Step-by-step explanation:

-2x+4+3y-5x-2y

Combine like terms

-7x+1y+4

evaluate

-7(-3) 1(4) 4

Solve

21+4+4

Nady [450]3 years ago

5 0

if x = - 3 and y = 4

<h3><u>simplification</u> </h3>

<h3><u>evaluation</u><u> </u></h3>

hope that helps !

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Carol Ann buys a TV at 70% off the original price. If she pays $120, what was the original price of the TV?

Keith_Richards [23]

If the TV is 70% off, then that means she paid 30% of the original cost. If 30% of the original cost is $120, then...

30% * x = 120
.30x = 120
x = 120/.30
x = 400

The original cost was $400

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Yes he has enough boxes to meet quota.

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2 years ago

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2 years ago

A court reporter is paid for her work by the hour. If she makes $75 for 5 hours of work, how much will she be paid for working 1

elena-s [515]

Answer:

Step-by-step explanation:

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3 years ago

Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.

blagie [28]

A.
$5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0$

B.
$3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}$

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
$3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 12 to both sides} \\
x=11$

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2 years ago