A proportional relationship is described by the equation
... y = k·x
The point (x, y) = (0, 0) is <em>always</em> a solution to this equation.
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In short, if the relationship is proportional, its graph will go through the origin. If the graph does not go through the origin, the relationship is not proportional.
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Note that this is true if the domain includes the origin. You can have y = kx <em>for x > 10 </em>and the graph will <em>not</em> go through the origin because the function is <em>not defined</em> there.
Answer:
![\sqrt[5]{a^{3} b^{2}c}](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B5%5D%7Ba%5E%7B3%7D%20b%5E%7B2%7Dc%7D)
Step-by-step explanation:
Rationalization factor of ![\sqrt[5]{a^2 b^3 c^4}](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B5%5D%7Ba%5E2%20b%5E3%20c%5E4%7D%20)
![= \sqrt[5]{a^{5-2} b^{5-3}c^{5-4}}\\= \sqrt[5]{a^{3} b^{2}c^{1}}\\= \sqrt[5]{a^{3} b^{2}c}\\](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B5%5D%7Ba%5E%7B5-2%7D%20b%5E%7B5-3%7Dc%5E%7B5-4%7D%7D%5C%5C%3C%2Fp%3E%3Cp%3E%3D%20%5Csqrt%5B5%5D%7Ba%5E%7B3%7D%20b%5E%7B2%7Dc%5E%7B1%7D%7D%5C%5C%3C%2Fp%3E%3Cp%3E%3D%20%5Csqrt%5B5%5D%7Ba%5E%7B3%7D%20b%5E%7B2%7Dc%7D%5C%5C%20)
Answer:
C. 3 cans
Step-by-step explanation:
9 1/9 times 3 is 27.33 and if one can cover 10 square meters then that means you'll need 3 cans.
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