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yuradex [85]
3 years ago
11

Please help me and explain please

Mathematics
1 answer:
Lyrx [107]3 years ago
4 0

Answer:

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Step-by-step explanation:

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Most individuals are aware of the fact that the average annual repair cost for an automobile depends on the age of the automobil
o-na [289]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Most individuals are aware of the fact that the average annual repair cost for an automobile depends on the age of the automobile. A researcher is interested in finding out whether the variance of the annual repair costs also increases with the age of the automobile. A sample of 26 automobiles 4 years old showed a sample standard deviation for annual repair costs of $120 and a sample of 23 automobiles 2 years old showed a sample standard deviation for annual repair costs of $100. Let 4 year old automobiles be represented by population 1.

State the null and alternative versions of the research hypothesis that the variance in annual repair costs is larger for the older automobiles.

At a 0.01 level of significance, what is your conclusion? What is the p-value?

Answer:

Null hypotheses = H₀ = σ₁² ≤ σ₂²

Alternative hypotheses = Ha = σ₁² > σ₂²

Test statistic = 1.44

p-value = 0.1954

0.1954 > 0.01

Since the p-value is greater than the given significance level therefore, we cannot reject the null hypothesis.

We can conclude that there is no sufficient evidence to support the claim that the variance in annual repair costs is larger for older automobiles.

Step-by-step explanation:

Let σ₁² denotes the variance of 4 years old automobiles

Let σ₂² denotes the variance of 2 years old automobiles

State the null and alternative hypotheses:

The null hypothesis assumes that the variance in annual repair costs is smaller for older automobiles.

Null hypotheses = H₀ = σ₁² ≤ σ₂²

The alternate hypothesis assumes that the variance in annual repair costs is larger for older automobiles.

Alternative hypotheses = Ha = σ₁² > σ₂²

Test statistic:

The test statistic is given by

Test statistic = σ₁²/σ₂²

Test statistic = 120²/100²

Test statistic = 1.44

p-value:

The degree of freedom corresponding to 4 years old automobiles is given by

df₁ = n - 1  

df₁ = 26 - 1  

df₁ = 25

The degree of freedom corresponding to 2 years old automobiles is given by

df₂ = n - 1  

df₂ = 23 - 1  

df₂ = 22

Using Excel to find out the p-value,  

p-value = FDIST(F-value, df₁, df₂)

p-value = FDIST(1.44, 25, 22)

p-value = 0.1954

Conclusion:

When the p-value is less than the significance level then we reject the Null hypotheses

p-value < α   (reject H₀)

But for the given case,

p-value > α

0.1954 > 0.01

Since the p-value is greater than the given significance level therefore, we cannot reject the null hypothesis.

We can conclude that there is no sufficient evidence to support the claim that the variance in annual repair costs is larger for older automobiles.

8 0
3 years ago
There are 5 exams in a semester. You have scored 77, 90, 85, and 100 on the previous four exams. What must you make on the fifth
siniylev [52]

Answer:

<h2>The correct answer for this question is 78.</h2>

Step-by-step explanation:

  • The average or mean of any variable or mathematical phenomenon is calculated as the division of the sum of all the numbers or items within the particular variable by the total number of items or numbers within the variable.
  • In this case, the marks of the 4 exams in the semester are 77,90,85 and 100 respectively.There are total 5 exams in the semester.
  • Let's suppose that the marks for the 5th exam is x.
  • Therefore, based on the mathematical formula to compute average or mean,to get an overall average of 86 including all the 5 exams, one has to get:-

   \frac{77+90+85+100+x}{5}=86

  77+90+85+100+x=430

  x=430-77-90-85-100

  x=78

  • Hence, based on the above calculations,one has has to get 78 on the 5th exam to obtain an overall average of exactly 86.

5 0
3 years ago
PLEASE HELP!! Find an equation for the graph, Write in form y=AsinBx or y=AcosBx.
Zepler [3.9K]

Answer:

4cos4x

Step-by-step explanation:

let's use cos

amplitude=4

period=pi/2

2pi/x=pi/2

x=4

no phase shift

y=4cos4x

pic from desmos

5 0
2 years ago
The circumference of the great wheel was twelve thousand and forty-one thousand inches. The cricumference of the lesser wheel wa
Korvikt [17]

Answer:

The larger wheel is 10979.04098 more than the smaller wheel.

Step-by-step explanation:

Given that,

The circumference of the great wheel was twelve thousand and forty-one thousandth inches.

C = 12000.041 inches

The circumference of the lesser wheel was only one thousand twenty-one and two hundred-thousand inches.

C' = 1021.00002 inches

We need to find how much larger was the great wheel. To find it, take the difference of C and C'.

C-C' = 12000.041 inches - 1021.00002 inches

= 10979.04098 inches

Hence, the larger wheel is 10979.04098 more than the smaller wheel.

5 0
3 years ago
Max has two cats. Rex and Roman. If Rex weighs 11 7/18 pounds and Roman weighs 11.329 pounds, which cat weighs the most?​
Vinvika [58]

Answer: Rex weighs more.

Step-by-step explanation:

You have to change both of the numbers into the same form. I did decimal form.

Rex - 11 7/18 = 11.389 (rounded to the hundredths)

Roman - 11.329

Rex is bigger.

<u><em>Hope this helps!</em></u>

8 0
2 years ago
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