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german
3 years ago
15

A class sold tickets for a dance. Student tickets cost $2 and faculty tickets cost $2.50. A total of $450 was collected and 216

tickets were sold. How many faculty tickets were sold?
Mathematics
1 answer:
WITCHER [35]3 years ago
3 0

If all 216 tickets sold were faculty tickets, the revenue would be 216 * 2.5, or $540

The actual revenue collected was $450. The difference between $540 and $450 is $90.

The difference between the student and faculty tickets are $2.50-$2, or .50

$90.00 / .50 = 180 student tickets sold.

That leaves 216-180, or 36 as faculty tickets.

180 student tickets at $2 = $360

36 faculty tickets at $2.50 = $90

$360 + $90 = $450

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Sophie [7]

Answer:The answer is 3.5273684211

Step-by-step explanation:

I your round it up then it would be 3.5

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3 years ago
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Bonnie is four years older than Clyde.
Doss [256]

Answer:

Bonnie's age is 18

Step-by-step explanation:

Let

x ----> Bonnie's age

y ---> Clyde's age

we know that

x=y+4 ----> equation A

x-10=2(y-10)

x-10=2y-20

x=2y-20+10

x=2y-10 ----> equation B

substitute equation A in equation B

y+4=2y-10

Solve for y

2y-y=4+10

y=14

<em>Find the value of x</em>

x=14+4=18

therefore

Bonnie's age is 18

Clyde's age is 14

7 0
3 years ago
Springfield nuclear energy inc bonds are currently trading at 283.30. The bonds have a face value of $1,000, a coupon rate of 2%
vampirchik [111]

<u>Answer:</u>

The yield to maturity of the bonds is 11%

<u>Explanation:</u>

Price at which the bonds is currently trading = 283.30$

Face Value = $1000

Coupon rate = 2%

Hence the coupon bond rate = $1000 ×2%

= 1000\times \frac{2}{100}

=$20

Years to maturity: 20 years

Formula used:  

=\frac{(C+ (\frac{(F-P)}{n}))}{(\frac{(F+P)}{2})}

Where C is the bond coupon rate

F is the face value

P is the price

N is the number of years

=\frac{(20 +(\frac{(1000-283.30)}{20})}{(\frac{(1000+283.30)}{2})}

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3 0
3 years ago
78 : 120 :: ? : 66<br>please give answer with explanation<br>​
yawa3891 [41]

Step-by-step explanation:

<u>Method</u><u> </u><u>1</u><u>:</u>

Given that:

78 : 120 :: ? : 66

Here,

Product of extremes = 78 and 66

Product of means = 120 and ?

so,

(78*66) = (120 * ?)

⇛5148 = 120 * ?

⇛5148 = 120?

⇛120? = 5148

Shift the number 120 from LHS to RHS, changing it's sign.

⇛? = 5148/120

Therefore, (?) = 42.9

<u>Method</u><u> </u><u>2</u><u>:</u>

78 : 120 :: ? : 66

Convert each ratio into fraction.

⇛78/120 = ?/66

On applying cross multiplication then

since, (a/b) = (c/d) ⇛cd = ad

Where, a = 78, b = 120, c = ? and d = 66

Now,

⇛(120)? = (78)66

⇛120? = 5148

⇛(?) = 5148/120

Therefore, (?) = 42.9

<u>Ans</u><u>w</u><u>er:</u> Hence the value of (?) for the given problem is 42.9.

<u>Verification</u><u>:</u>

Check whether the value of (?) is true or false.

78 : 120 :: ? : 66

Substitute the value of (?).

⇛78:120 = 42.9:66

Product of extremes should be equal to product of means.

Product of extremes:- 78*66 = 5148

Product of means:- 120*42.9 = 5148

⇛5148 = 5148

LHS = RHS

Hence, verified.

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alisha [4.7K]

Answer:

Easy -2x

Step-by-step explanation:Because both a positive y and a negative y cancle out eachother so all thats left is both of the negative x's

4 0
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