Answer:
The correct answer is B.
Step-by-step explanation:
In order to find this, calculate out the discriminant for each of the following equations. If the discriminant is a perfect square, then it can be factored.
Discriminant = b^2 - 4ac
The only of the equations that does not yield a perfect square is B. The work for it is done below for you.
Discriminant = b^2 - 4ac
Discriminant = 7^2 - 4(2)(-5)
Discriminant = 49 + 40
Discriminant = 89
Since 89 is not a perfect square, we cannot factor this.
Answer:
x = 15 degrees
3 angles in triangle are 44, 44 and 92 degrees.
Step-by-step explanation:
When the lines are parallel the internal angles add up to 180 degrees. So:-
8x + 7 + 2x + 23 = 180
10x + 30 = 180
10x = 150
x = 15
In the triangle:-
The angle adjacent to 136 = 180 - 136
= 44 degrees. As 2 sides of the triangle are congruent the other base angle = 44 degrees also.
The third angle = 180 - 2(44) = 92 degrees
You can not simplify 7/10 because 7 os only on 1 and 7s times table.
Answer:
The stock price beyond which 0.05 of the distribution fall is $12.44.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Mean of $8.52 with a standard deviation of $2.38
This means that 
The stock price beyond which 0.05 of the distribution fall is
This is the 100 - 5 = 95th percentile, which is X when Z has a pvalue of 0.95. So X when Z = 1.645.




The stock price beyond which 0.05 of the distribution fall is $12.44.
Happy New Year from MrBillDoesMath!
Answer:
1, -2, -3
Discussion:
The real roots of the polynomials are factors of the last term (6) divided by the first term (1). The factors of 6/1 or 6 are 1,2,3, and 6. I found by substitution that x= 1 was a solution, divided the polynomial by x-1, came up with a quadratic (x^2 + 5x + 6), and found the remaining roots via the quadratic formula.
Thank you,
MrB