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2 years ago

Find the value of x for g(x) = -x + 5 when g(x) = 2.

Mathematics

2 answers:

Lana71 [14]2 years ago

7 0

Answer:

Step-by-step explanation:

harina [27]2 years ago

3 0

The answer is -3.
Explanation:
1. Substitute
2. Use Order of operation

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Use the Two-Transversal Proportionality Corollary to find the value of x.

Artist 52 [7]

I hope this helps you

12/12+x=13/13+26

12/12+x=13/39

12/12+x=1/3

12+x=36

x=24

5 0

2 years ago

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The ratio for 42 pens : 35 pencils as a fraction is

Alex73 [517]

As a fraction,
35/42, simplified, 5/6
answer=5/6
hope this helps....

4 0

2 years ago

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For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

.12÷.6492 is what answer

White raven [17]

Answer:

.000018484

Step-by-step explanation:

You divide them and that is what your calculator says

4 0

3 years ago

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A line passes through the point (–2, 7) and has a slope of –5. A coordinate plane. What is the value of a if the point (a, 2) is

Nana76 [90]

Y = mx + c

7= (-5)(-2)+ c

7= 10 +c

7-10=c

-3=c

Equation of the line: y = -5x-3

Sub in (a, 2)

2= - 5(a)-3

2+3= -5a

5= - 5a

1= - a

A = -1

8 0

2 years ago

Read 2 more answers