Answer:
Price of One Bush is $ 23
Explanation:
Suppose
bushes = B
trees = T
According to given condition:
13B + 4T = 487 (Eq: 1)
6B + 2T = 232 (Eq: 2)
Multiplying (Eq: 2) by 2
12B + 4T = 464 (Eq: 3)
Substractign (Eq: 3) from (Eq: 1)
13B + 4T - (12B + 4T) = 487 - 464
13B + 4T - 12B - 4T = 23
B = 23
By putting value of B in (Eq: 1)
(13 x 23) + 4T = 487
299 + 4T = 487
4T = 487 - 299
4T = 188
T = 188 / 4
T = 47
Price of One Bush = B = 23
Answer:
$130,000
Explanation:
For determining the additional life insurance required first we need to follow some steps which are shown below:-
Step 1
Total needs = Cash needs + Income needs + Special needs
= $30,000 + $140,000 + $100,000
= $270,000
Step 2
Total assets held = Bank accounts + Retirement plans + Investment accounts
= $20,000 + $30,000 + $40,000
= $90,000
Step 3
Total amount of life = $270,000 - $90,000
= $180,000
and finally
Additional life insurance required =
The Total amount of life - Life insurance provided by the employer
= $180,000 - $50,000
= $130,000
Maybe talk about how you're life has been, or what you struggle with and wish to move on from it. Be creative ideas are endless! Or base it on a topic about your life. For example, if you've ever gotten bullied talk about how you felt through that time.
Answer:
<u>Maximum Amount that can be loanded = $4139619</u>
Explanation:
DSCR = NOI / Debt Service
Debt Service = Principal + Interest
NOI = $ 500000
Debt Service = 500000 / 125 % = $ 400,000
The loan would be ammortized monthly over a period of 25 years.
Monthly Payment or EMI
E = P×r×(1 + r)n/ ((1 + r)n - 1)
12E = 400,000 = [P×r×(1 + r)n/ ((1 + r)n - 1)] * 12
or, P = 400000 / 0.0966272500154557 = $4139619
<u>Maximum Amount that can be loanded = $4139619</u>
Answer:
3,300 defects
Explanation:
If there are 5 defect opportunities per unit, and 2,000 units were inspected, the number of defects per opportunity observed was:
![DPO = \frac{33}{5*2,000}\\DPO=0.0033](https://tex.z-dn.net/?f=DPO%20%3D%20%5Cfrac%7B33%7D%7B5%2A2%2C000%7D%5C%5CDPO%3D0.0033)
Therefore, the number of defects per 1 million opportunities (DPMO) is:
![DPMO = 0.0033*1,000,000\\DPMO = 3,300](https://tex.z-dn.net/?f=DPMO%20%3D%200.0033%2A1%2C000%2C000%5C%5CDPMO%20%3D%203%2C300)
The number of defects per 1 million opportunities (DPMO) for this process is 3,300.