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3 years ago

Which answer is it A B C or D

Mathematics

1 answer:

Tamiku [17]3 years ago

6 0

The answer to this question is c

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The viewing angle to a vertical screen is 18 degrees and the distances between the viewing point P and the top and the top and b

andrey2020 [161]

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3 years ago

Select the correct answer. Find the solution(s) for x in the equation below.<br> x2-9x+20=0

trasher [3.6K]

Step-by-step explanation:

Given

x² - 9x + 20 = 0

x² - ( 4 + 5) x + 20 = 0

x² - 4x - 5x + 20 = 0

x ( x - 4 ) - 5 (x - 4 ) = 0

(x - 4 ) ( x - 5 ) = 0

Either

x - 4 =0

x = 4

x - 5 =0

x = 5

x = 4 and 5

Hope it will help :)

$.)$

8 0

3 years ago

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Which expression represents the total perimeter of her sandwich, and if x = 1.2, what is the approximate length of the crust?

Cerrena [4.2K]

A____________________

3 0

3 years ago

Integrate the following

enot [183]

I suppose you mean to have the entire numerator under the square root?

$\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx$

We can use a trigonometric substitution to start:

$x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt$

Then for $x=2$ , $t=\sec^{-1}1=0$ ; for $x=4$ , $t=\sec^{-1}2=\frac\pi3$ . So the integral is equivalent to

$\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt$

We can write

$\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t$

so the integral becomes

$\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}$

7 0

3 years ago

The volume of a cube with side x is calculated by

Sphinxa [80]

Answer:

${x}^{3}$

Step-by-step explanation:

$volume \: \: \: of \: \: \: a \: \: cube \\ = whl \\ = x \times x \times x \\ = {x}^{3}$

hope this helps

brainliest appreciated

good luck! have a nice day!

6 0

3 years ago

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