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mars1129 [50]
3 years ago
12

3x^2 -5x -2=0

Mathematics
2 answers:
Kipish [7]3 years ago
6 0

Answer:

Step-by-step explanation:

1. Find two numbers that add to make the coefficient of x (in this case, -5) and that multiply to make the constant term multiplied by the coefficient of x^2 (in this case, -2 x 3 = -6)

Two numbers that work are -6 and +1

-6 x +1 = -6

-6 + -1 = -5

2. Split the middle term into the two numbers that you found.

3x^2 -6x +x -2 = 0

I've put the -6 on the left side because in our next step, when we factorise, it will be easier than having the numbers the other way around.

3. Factorise the left side by taking out common factors from each pair. The pairs I'm talking about here are '3x^2 and -6x', and 'x and -2'

3x (x-2) +1 (x-2) = 0

4. You now have two numbers both being multiplied by the term x-2. We can rearrange this equation to give us two brackets being multiplied by each other.

(3x + 1) (x-2) = 0

5. According to the Null Factor Law, if two terms are multiplied together and the result is 0, then one of those terms must be 0. Make both terms equal to 0 and solve each for x.

3x + 1 = 0              x-2 = 0

3x = -1                   x = 2

x = -1/3

6. The solutions to this equation are x = 2 and x = -1/3

Ronch [10]3 years ago
3 0

Answer:

Step-by-step explanation:

Start by separating (not factoring) -5x.  For example, we might get {-2x, - 3x} (note how these combine to produce -5x).  Might have to try several combinations to find the right one.

Then 3x^2 -5x -2=0 could possibly be x(3x - 2) - (3x - 2), or

                                                                x(3x - 2) - 1(3x - 2).

Notice how the factor (3x - 2) shows up twice.  If we factor out (3x - 2) we are left with (x - 1).  We check these results by multiplying (3x - 2) and (x - 1) together, so we can be sure that the result is the original 3x^2 -5x -2=0.

(3x - 2)(x - 1) = 3x^2 - 3x - 2x + 1 results in 3x^2 - 5x + 2.  Unfortunately, the sign of that 2 is incorrect; we'd hoped for -2, not +2.

To check this further, I used synthetic division with 1 as divisor; the remainder is -4, which tells us that (x - 1) is not a factor of 3x^2 -5x -2=0.

Please double check to ensure that you have copied this problem down correctly.

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Determine an approximate value for y if the coordinate (-0.5387 ,y) is on the unit circle
adoni [48]

Answer:

y = 0.8425   or   y = -0.8425

Step-by-step explanation:

All points in the Cartesian coordinate system have an x and y coordinate, defined by two perpendicular measurements.

If the point is on the unit circle, then the radius of the circle is defined to be 1 unit, and the corresponding right triangle follows the Pythagorean Theorem.

a^2+b^2=c^2

For a unit circle:

x^2+y^2=1^2

Substituting the known value for x, and simplifying...

(-0.5387)^2+y^2=(1)^2

0.29019769+y^2=1

Subtracting 0.29019769 from both sides to begin to isolate "y"...

y^2=1-0.29019769

y^2=0.70980231

Applying the square root property...

\sqrt{y^2}=\pm \sqrt{0.70980231}

y=\pm 0.8424976171...

So, (to 4 decimal places), the y coordinate could be either 0.8425 or -0.8425.

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3 0
2 years ago
I need help. please help guys. this is a struggle.
djyliett [7]

Answer:

Option C

Step-by-step explanation:

By the property of a parallelogram,

"Opposite angles of a parallelogram are equal in measure"

m∠L = m∠N

Since, m∠L = 106°

Therefore, m∠N = 106°.

Option C will be the correct option.

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