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allochka39001 [22]
3 years ago
10

The viewing angle to a vertical screen is 18 degrees and the distances between the viewing point P and the top and the top and b

ottom of the screen are 25m and 23m, respectively. Find the height of the screen (x m), correct to the nearest centimetre

Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0

Check the attachment!!!

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If the scale factor is 5, how many times larger will the scaled copy's area be?
Lady bird [3.3K]

Answer:

25 times

Step-by-step explanation:

Scale factor is the ratio of dimensions of the image and the preimage.

Scale factor = \frac{\text{Side length of image}}{\text{Side length of preimage}}

Since area of a figure is the square of dimensions.

Area = Length × Width

Therefore, area scale factor will be the ratio of square of the dimensions of image and preimage.

Area scale factor = \frac{\text{Area of the image}}{\text{Area of the preimage}}

                             = (Scale factor)²

                             = 5²

                             = 25

Therefore, area of the image will be 25 times the area of the preimage.

4 0
3 years ago
I need help fast
hram777 [196]

Answer:

On a coordinate plane, a line goes through (0, 3) and (2, 4) and another line goes through (0, 3) and (0.75, 0).

This answer almost coincide with option C. I suppose there was a mistype.

Step-by-step explanation:

The system of equations is formed by:

–x + 2y = 6

4x + y = 3

In the picture attached, the solution set is shown.

The first equation goes through (0, 3) and (2, 4), as can be checked by:

–(0) + 2(3) = 6

–(2) + 2(4) = 6

The second goes through (0, 3) and (0.75, 0), as can be checked by:

4(0) + (3) = 3

4(0.75) + (0) = 3

7 0
3 years ago
Read 2 more answers
Integrate t sec^2 (2t) dt
Neporo4naja [7]
F = t ⇨ df = dt 
dg = sec² 2t dt ⇨ g = (1/2) tan 2t 
⇔ 
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt 
u = 2t ⇨ du = 2 dt 

As integral of tan u = - ln (cos (u)), you get : 

integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant 
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant 
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer 
8 0
4 years ago
Read 2 more answers
I need help on this question can anyone please help me
MAVERICK [17]

9514 1404 393

Answer:

  p = -9 5/9

Step-by-step explanation:

Undo what is done to p.

Multiply by 2.

  p +10 = 4/9

Subtract 10.

  p = 4/9 -10

  p = -9 5/9

8 0
3 years ago
Factorize completely the following algebra expression :<br>81x^4-16y^8​
ohaa [14]
Here’s your answer the A/= it means the answer is okay.

6 0
3 years ago
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