Min {sin(x) | 0 is les than or equal to x less than or greater than or equal to 2 pie = -1 at x = 3 pie over 2
H = 2sqrt2
D = 6sqrt3
In a 45,45,90 triangle the hypotenuse is (x)sqrt2 while the side lengths are equivalent being a single value x. Therefore, when given the hypotenuse and solving for the leg, divide 4 by sqrt2 to get 4sqrt2/2 which simplifies to 2sqrt2 when the denominator and numerator cancel.
In a 30,60,90 triangle the short leg x is across from the 30 degree angle meaning the angle across from the 60 degree angle is x times the sqrt of 3. Therefore the long leg is 6sqrt3
Answer:
see explanation
Step-by-step explanation:
The sum to n terms of an arithmetic sequence is
= 
[ 2a₁ + (n - 1)d ]
where a₁ is the initial value and d the common difference
Given
= [ 10 + (n - 1)3 ]
Then by comparison
2a₁ = 10 ( divide both sides by 2 )
a₁ = 4 ← initial value
and d = 3 ← common difference
Thus
= 
[ 10 + (7 × 3) ]
= 4(10 + 21)
= 4 × 31
= 124
1) Diameter = Line MN, Chord = Line LN
<span>2) B --- GFC </span>
<span>3) C --- GCE </span>
