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Akimi4 [234]
3 years ago
5

A certain rectangle has a perimeter of 22 units and an area of 30 square units. two of the vertices have coordinates at (2,2) an

d (2,7). find the two missing coordinates. use the coordinate plane to support your answer
Mathematics
1 answer:
Zigmanuir [339]3 years ago
5 0
2* (width + length) = 22 which can be restated

A) 2w + 2L = 22

Dividing "A" by 2 we get
A) w + L = 11
B) width * length = 30
length = 30 / width and we put this into equation "A"
 w + 30/width = 11
Multiplying both sides by width
width^2 + 30 = 11w

w^2 -11w + 30 =0
width = 5 and/or width =6
Therefore length = 5 and/or length =6
(2,2) (2,7)
Difference in x = 0 and difference in y = 5
So, we'll make x=6 and the 2 other coordinates are
(8, 2) and (8, 7)

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3 years ago
Please solve with working much appreciated
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Answer:

x°= 55°

Step-by-step explanation:

First, find the degrees of the larger triangle.

Since every triangle equals 180° degrees, make an equation.

60°+90°+a°= 180°

Now, add the degrees together.

120°+a°= 180°

Then subtract from both sides.

120°+a°= 180°

-120 °      -120°

a°= 60°

Now that you know the sum of all the angles, subtract 25° from 60°(which is the measure of a).

60°-25°= 35°

Now that we have the measurement of the angle from the smaller triangle inside the larger one, make an equation.

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Then, add the degrees.

125°+x°= 180°

Subtract from both sides of the equation to get the answer for the variable.

125°+x°= 180°

-125°       -125°

x°= 55°

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3 years ago
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Step-by-step explanation:

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