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Nataly_w [17]
3 years ago
6

What does this mean? 20 points + brainleist! What other angle measures or side lengths can you determine using these added figur

es? List all the concepts and facts you use.

Mathematics
1 answer:
mel-nik [20]3 years ago
3 0

Step-by-step explanation:

<em>The</em><em> </em><em>question</em><em> </em><em>has</em><em> </em><em>asked</em><em> </em><em>you</em><em> </em><em>to</em><em> </em><em>have</em><em> </em><em>another</em><em> </em><em>concepts</em><em> </em><em>or</em><em> </em><em>facts</em><em> </em><em>that</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>used</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>other</em><em> </em><em>angles</em><em> </em><em>and</em><em> </em><em>measure</em><em> </em><em>of</em><em> </em><em>side</em><em> </em><em>length</em><em>.</em>

<em>by</em><em> </em><em>looking</em><em> </em><em>the</em><em> </em><em>fig</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>determine</em><em> </em><em>various</em><em> </em><em>sides</em><em> </em><em>and</em><em> </em><em>angles</em><em> </em><em>as</em><em> </em><em>all</em><em> </em><em>are</em><em> </em><em>joined</em><em> </em><em>together</em><em>.</em>

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99 POINT QUESTION, PLUS BRAINLIEST!!!
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First, we have to convert our function (of x) into a function of y (we revolve the curve around the y-axis). So:


y=100-x^2\\\\x^2=100-y\qquad\bold{(1)}\\\\\boxed{x=\sqrt{100-y}}\qquad\bold{(2)} \\\\\\0\leq x\leq10\\\\y=100-0^2=100\qquad\wedge\qquad y=100-10^2=100-100=0\\\\\boxed{0\leq y\leq100}

And the derivative of x:

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Now, we can calculate the area of the surface:

A=2\pi\int\limits_0^{100}\sqrt{100-y}\sqrt{1+\left(-\dfrac{1}{2\sqrt{100-y}}\right)^2}\,\,dy=\\\\\\= 2\pi\int\limits_0^{100}\sqrt{100-y}\sqrt{1+\dfrac{1}{4(100-y)}}\,\,dy=(\star)

We could calculate this integral (not very hard, but long), or use (1), (2) and (3) to get:

(\star)=2\pi\int\limits_0^{100}1\cdot\sqrt{100-y}\sqrt{1+\dfrac{1}{4(100-y)}}\,\,dy=\left|\begin{array}{c}1=\dfrac{-2\sqrt{100-y}}{-2\sqrt{100-y}}\end{array}\right|= \\\\\\= 2\pi\int\limits_0^{100}\dfrac{-2\sqrt{100-y}}{-2\sqrt{100-y}}\cdot\sqrt{100-y}\cdot\sqrt{1+\dfrac{1}{4(100-y)}}\,\,dy=\\\\\\ 2\pi\int\limits_0^{100}-2\sqrt{100-y}\cdot\sqrt{100-y}\cdot\sqrt{1+\dfrac{1}{4(100-y)}}\cdot\dfrac{dy}{-2\sqrt{100-y}}=\\\\\\

=2\pi\int\limits_0^{100}-2\big(100-y\big)\cdot\sqrt{1+\dfrac{1}{4(100-y)}}\cdot\left(-\dfrac{1}{2\sqrt{100-y}}\, dy\right)\stackrel{\bold{(1)}\bold{(2)}\bold{(3)}}{=}\\\\\\= \left|\begin{array}{c}x=\sqrt{100-y}\\\\x^2=100-y\\\\dx=-\dfrac{1}{2\sqrt{100-y}}\, \,dy\\\\a=0\implies a'=\sqrt{100-0}=10\\\\b=100\implies b'=\sqrt{100-100}=0\end{array}\right|=\\\\\\= 2\pi\int\limits_{10}^0-2x^2\cdot\sqrt{1+\dfrac{1}{4x^2}}\,\,dx=(\text{swap limits})=\\\\\\

=2\pi\int\limits_0^{10}2x^2\cdot\sqrt{1+\dfrac{1}{4x^2}}\,\,dx= 4\pi\int\limits_0^{10}\sqrt{x^4}\cdot\sqrt{1+\dfrac{1}{4x^2}}\,\,dx=\\\\\\= 4\pi\int\limits_0^{10}\sqrt{x^4+\dfrac{x^4}{4x^2}}\,\,dx= 4\pi\int\limits_0^{10}\sqrt{x^4+\dfrac{x^2}{4}}\,\,dx=\\\\\\= 4\pi\int\limits_0^{10}\sqrt{\dfrac{x^2}{4}\left(4x^2+1\right)}\,\,dx= 4\pi\int\limits_0^{10}\dfrac{x}{2}\sqrt{4x^2+1}\,\,dx=\\\\\\=\boxed{2\pi\int\limits_0^{10}x\sqrt{4x^2+1}\,dx}

Calculate indefinite integral:

\int x\sqrt{4x^2+1}\,dx=\int\sqrt{4x^2+1}\cdot x\,dx=\left|\begin{array}{c}t=4x^2+1\\\\dt=8x\,dx\\\\\dfrac{dt}{8}=x\,dx\end{array}\right|=\int\sqrt{t}\cdot\dfrac{dt}{8}=\\\\\\=\dfrac{1}{8}\int t^\frac{1}{2}\,dt=\dfrac{1}{8}\cdot\dfrac{t^{\frac{1}{2}+1}}{\frac{1}{2}+1}=\dfrac{1}{8}\cdot\dfrac{t^\frac{3}{2}}{\frac{3}{2}}=\dfrac{2}{8\cdot3}\cdot t^\frac{3}{2}=\boxed{\dfrac{1}{12}\left(4x^2+1\right)^\frac{3}{2}}

And the area:

A=2\pi\int\limits_0^{10}x\sqrt{4x^2+1}\,dx=2\pi\cdot\dfrac{1}{12}\bigg[\left(4x^2+1\right)^\frac{3}{2}\bigg]_0^{10}=\\\\\\= \dfrac{\pi}{6}\left[\big(4\cdot10^2+1\big)^\frac{3}{2}-\big(4\cdot0^2+1\big)^\frac{3}{2}\right]=\dfrac{\pi}{6}\Big(\big401^\frac{3}{2}-1^\frac{3}{2}\Big)=\boxed{\dfrac{401^\frac{3}{2}-1}{6}\pi}

Answer D.
6 0
4 years ago
Read 2 more answers
An ongoing promotion at a department store gives customers 20\%20%20, percent off the portion of their bill that is over \$100$1
gtnhenbr [62]

The equation best models the situation 100 + 0.8(x - 100) = 250.

The correct option is (D)

<h3>What is equation?</h3>

An equation in math is an equality relationship between two expressions written on both sides of the equal to sign.

The complete question is:

An ongoing promotion at a department store gives customers 20% off the portion of their bill that is over $100. Ruby's total bill at the department store after the promotion has been applied is $250. If x represents the amount of money Ruby would have spent on the same purchase at the department store without the promotion, which of the following equations best models the situation?

A. 0.2x + 100 = 250

B. 0.8x + 100 = 250

C. 100 + 0.2(x - 100) = 250

D. 100 + 0.8(x - 100) = 250

Given:

Department store gives 20 % off the portion of the bill that is over 100 dollars.

Total bill = 250

let x is the amount of money she would have spent without the promotion.

Then, cost after discount applies = 0.8 ( x - 100 ).

Hence, the equation is 100 + 0.8 (x - 100) = 250.

Learn more this concept here:

brainly.com/question/10952401

#SPJ1

7 0
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