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julia-pushkina [17]
3 years ago
14

Suppose a fair die is rolled eight times. find numerical values for the expectation

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0
Your possiblity is 1/6 then you multiply that by tries
so 1/6 ×8
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Solve 5x÷6=20.<br><br> The solution is x=
puteri [66]
We want to get x by itself
First we will multiply both sides by 6 to cancel out the 6 on the left
5x = 120
We then divide by 5 on both sides to get x by itself
x = 24
7 0
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Help help help help help just need answer
kirza4 [7]

Answer:

25 miles

Step-by-step explanation:

2 inches represents 10 miles ( divide both parts by 2 )

1 inch represents 5 miles , then

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[tex]\sqrt{49} <br> please answer correctly
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$14.40 for 4.5 pounds of beef
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6 0
2 years ago
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Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to
RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

5 0
3 years ago
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