Hello here is a solution :
x²-8y-6x+y²=4....(1)
A)
x²-6x = x²-2(3)x+9-9
= x²-2(3)x+3²-9
x²-6x =(x-3)² -9
B)
y²-8y = y²-2(4)y +4²-16
y²-8y = (y-4)²-16
C)
in (1) :
(x-3)² -9 +(y-4)²-16 = 4
(x-3)² +(y-4)² = 29 ...<span>is the standard form of the equation
</span> <span>Select answer 1 :
</span><span>A: 3
B: 4
C: (x−3)2+(y−4)2=29</span>
"The quotient of z and 4"
is the same as saying
"z divided by 4"
z/4
Answer:
h<-7/4
Step-by-step explanation:
1 → B
multiply each term in the parenthesis by the 6 outside
6(b-7) = 6b - 42
2 → D
multiply each term in the parenthesis by the 3 outside
3(4x+6y+2) = 12x+18y+6
3 → A
the value outside the parenthesis is -1, hence each term inside is multiplied by -1
-1(6x+5y) = -6x -5y
(3,4)(2,-1)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (-1-4) / (2 - 3) = -5/-1 = 5
y = mx + b
slope(m) = 5
u can use either of ur points...(3,4)...x = 3 and y = 4
now we sub and find b, the y int
4 = 5(3) + b
4 = 15 + b
4 - 15 = b
- 11 = b
so ur equation is : y = 5x - 11 <===
