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Bumek [7]
3 years ago
11

2cm 4cm 3.5cm volume of triangular prisms

Mathematics
1 answer:
spayn [35]3 years ago
6 0

14cm cubed

did that help

you multiply them together then divide by 2

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11-Across plus 28-Down
Art [367]

Answer:

(11,-28)

Step-by-step explanation:

8 0
3 years ago
Given g(x) = 10x + 2, find x when g(x) = 2.
Elan Coil [88]

Answer:

x=0    

Step-by-step explanation:

We are given:

g(x) =10x +2

and

g(x)=2

g(x) is equal to both 10x+2 and 2. Therefore, by substitution, we can set them equal to each other

10x+2=2

Now, we need to solve for x. First, move all the numbers to the same side. Subtract 2 from both sides

10x+2-2=2-2

10x=0

To solve for x, we have to get x by itself. x and 10 are being multiplied. To get x alone, divide both sides by 10.

10x/10=0/10

x=0

8 0
2 years ago
A year is a leap year if it is divisible by 4. but if the year is divisible by 100, it is a leap year only when it is also divis
KIM [24]
What is the question that you are asking?
3 0
3 years ago
a regular hexagonal nut of side 1 cm and length 3 cm with a central hole of diameter 1 cm. 3 cm 1 cm 1 cm. Calculate the volume
Bogdan [553]

Answer:

  5.44 cm³

Step-by-step explanation:

The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.

The area of a hexagon with side length s is given by ...

  A = (3/2)√3·s²

For s=1 cm, the area is ...

  A = (3/2)√3(1 cm)² = (3/2)√3 cm²

__

The area of a circle is given by ...

  A = πr²

The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...

  A = π(0.5 cm)² = 0.25π cm²

__

The volume is the face area multiplied by the length, so is ...

  V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³

  V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³

The volume of the metal is about 5.44 cm³.

5 0
2 years ago
What is the solution of square root of x plus twelve equals x
Bess [88]

Answer:

x=4

Step-by-step explanation:

√x+12=x

x+12=x2(Square both sides)

x+12=x2

x+12−x2=x2−x2(Subtract x^2 from both sides)

−x2+x+12=0

(−x−3)(x−4)=0(Factor left side of equation)

−x−3=0 or x−4=0(Set factors equal to 0)

x=−3 or x=4

x=−3(Doesn't work in original equation)

x=√x+12

7 0
3 years ago
Read 2 more answers
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