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2 years ago

Find the circumference and the area of a circle with the diameter of 8 m.

Mathematics

2 answers:

maksim [4K]2 years ago

4 0

Answer:

circumference = 8 x 3.14 = 25.12 m

area = 3.14(4²) = 50.24 m²

Step-by-step explanation:

irga5000 [103]2 years ago

3 0

Answer:

C= about 25.13

A= about 50.27

Step-by-step explanation:

The formula for circumference is 2* pi* r

The formula for area is pi *r^2

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Diego is solving the equation x^2-12x = 21

uysha [10]

Answer:

The solutions to the quadratic equations will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

Step-by-step explanation:

Given the expression

$x^2-12x\:=\:21$

Let us solve the equation by completing the square

$x^2-12x\:=\:21$

Add (-6)² to both sides

$x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2$

simplify

$x^2-12x+\left(-6\right)^2=57$

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

$x^2-12x+\left(-6\right)^2=\left(x-6\right)^2$

so the expression becomes

$\left(x-6\right)^2=57$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-6=\sqrt{57}$

add 6 to both sides

$x-6+6=\sqrt{57}+6$

Simplify

$x=\sqrt{57}+6$

also solving

$x-6=-\sqrt{57}$

add 6 to both sides

$x-6+6=-\sqrt{57}+6$

Simplify

$x=-\sqrt{57}+6$

Therefore, the solutions to the quadratic equation will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

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2 years ago

Mia says that in the number 5,555, all the digits have the same value.is she correct?explain why or why not.

ANEK [815]

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Gnesinka [82]

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3 years ago

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Answer:

[2, 15]

Step-by-step explanation:

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Katen [24]

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