Para hacer postres Maru compró 3/6 kg de azúcar y 4/6 de kg de harina, si el kg de los dos productos vale $16, ¿por cual de los
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Given the values of the three sides of the triangle, we can apply the Cosine Law to find the angles of the triangle. Recall that for we can express the value of c through the equation below.
Rearranging this equation, we can find the value ∠C as shown below.
We can apply the same reasoning for finding the value of ∠B as shown.
Plugging in the values of the sides (see image attached) from the given. It will now be straightforward to compute for ∠B and ∠C.
Answer: ∠C = 37.19° and ∠B = 53.13°
Rearranging this equation, we can find the value ∠C as shown below.
We can apply the same reasoning for finding the value of ∠B as shown.
Plugging in the values of the sides (see image attached) from the given. It will now be straightforward to compute for ∠B and ∠C.
Answer: ∠C = 37.19° and ∠B = 53.13°
The picture in the attached figure
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is
4x²
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is
4x²