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almond37 [142]
3 years ago
6

Para hacer postres Maru compró 3/6 kg de azúcar y 4/6 de kg de harina, si el kg de los dos productos vale $16, ¿por cual de los

productos pagó más?
Mathematics
1 answer:
slava [35]3 years ago
3 0

Answer:

Ella pagó más por harina

Step-by-step explanation:

En esta pregunta, tenemos la tarea de elegir qué azúcar o harina pagó más para hacer el postre.

Para calcular esto, lo que debemos hacer es multiplicar el costo por kg por la fracción del kg comprado

Para el suagar, el costo se calcula como 3/6 × 16 = $ 8

Para la harina, el costo se calcula como 4/6 × 16 = $ 10.67

Como se ve en los dos costos, podemos deducir que ella pagó más por la harina ya que tiene el mayor de los dos valores.

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[Question 1]
let d = number of dramas Gina rented, c = # of comedies, and t = # of documentaries:

[equation a] d + c + t = 11
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Now put in 3 for t in [d] or [e] to solve for c:
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