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almond37 [142]
3 years ago
6

Para hacer postres Maru compró 3/6 kg de azúcar y 4/6 de kg de harina, si el kg de los dos productos vale $16, ¿por cual de los

productos pagó más?
Mathematics
1 answer:
slava [35]3 years ago
3 0

Answer:

Ella pagó más por harina

Step-by-step explanation:

En esta pregunta, tenemos la tarea de elegir qué azúcar o harina pagó más para hacer el postre.

Para calcular esto, lo que debemos hacer es multiplicar el costo por kg por la fracción del kg comprado

Para el suagar, el costo se calcula como 3/6 × 16 = $ 8

Para la harina, el costo se calcula como 4/6 × 16 = $ 10.67

Como se ve en los dos costos, podemos deducir que ella pagó más por la harina ya que tiene el mayor de los dos valores.

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10. MP Find the Error The rate of growth for a
Akimi4 [234]

Answer:

the error is how many days it will take for the plant to grow 3.6 centimeters they have 1.44 but the correct answer is 9 days.

Step-by-step explanation:

it will take the plant 9 days to grow 3.6 centimeters

4 0
2 years ago
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
If anyone can help with number 4
Klio2033 [76]
If you do 27-12 (which is 15) you add 15 to 13 and 20
3 0
3 years ago
solve for x and round to the nearest tenth. this is geometry. I will mark Brainliest. please help &lt;3
Amiraneli [1.4K]

Answer:

x= 41.8°

Step-by-step explanation:

use inverse trig to find x.

sin^{-1}(\frac{4}{6})=x

type this into your calculator. (make sure the mode on your calculator is degree or it won't work)

x= 41.8

Hope This Helps:)

brainliest please

5 0
2 years ago
Marcus is making homemade barbecue sauce.The recipe caps for 3 cups of ketchup for every 1/2 cup of mustard
SSSSS [86.1K]

Answer:

3 divided  by 1/2

Step-by-step explanation:

turn 3 into 3/1  then flip 1/2 into 2/1 and multiply which is <u><em>6</em></u>

Kcf

Keep

Change

Flip

3 0
3 years ago
Read 2 more answers
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