Answer:
ASA
Step-by-step explanation:
You can show the angles at either end of segment BC in triangles MBC and LCB are congruent, so you have two angles and the segment between. The appropriate theorem in such a case is ASA.
4 ^ (1/7 ) is the 7th root of 4 or the 3rd box
4 ^ (7/2) is 4 to the 7th power then the square root or the 2nd box
7 ^ (1/4) is the 4th root of 7 or the 4th box
7 ^ (1/2) is the square root of 7 or the 6th box
… z =w …angle v x w = angle z x y
It follows AAA SIMILARITY Relation
THE ANSWER IS LYFE 3432423
