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4 years ago

Melissa had 9 stamps after she sold 4 stamps at the stamp show. How many stamps did she have before the show?

Mathematics

2 answers:

DENIUS [597]4 years ago

7 0

Add 9 and 4, that’s how many stamps she had before the show.

Sauron [17]4 years ago

3 0

If you add 9+4 you get 13 so Melissa has 13 stamps now :)

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Please Help! Algebra 2!

eduard

Answer:

The interest rate of the account is $3\%$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=14\ years\\ P=\$1,863\\ A=\$2,830.97\\n=4$

substitute in the formula above and solve for r

$\$2,830.97=\$1,863(1+\frac{r}{4})^{4*14}$

$(2,830.97/1,863)=(1+\frac{r}{4})^{56}$

$(2,830.97/1,863)^{1/56}=(1+\frac{r}{4})$

$[(2,830.97/1,863)^{1/56}-1]=\frac{r}{4}$

$r=4*[(2,830.97/1,863)^{1/56}-1]\\ \\r= 0.03$

Convert to percent

$r= 0.03*100=3\%$

8 0

3 years ago

Find the median, lower quartile, and upper quartile for the set of data.

Irina-Kira [14]

Answer:

The median is 2 lower quartile is 11 and upper quartile is 6

Step-by-step explanation:

hope this helps

5 0

3 years ago

10 multiplied by 1/5

Bingel [31]

10* (1/5)
= 10/5
= 2

The final answer is 2~

6 0

4 years ago

Read 2 more answers

Rewrite with only sin x and cos x.

Annette [7]

Option A

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Solution:

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

$cos 3x = cos(x + 2x)$

We know that,

$\cos (a+b)=\cos a \cos b-\sin a \sin b$

Therefore,

$\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x$ ---- eqn 1

We know that,

$\sin 2 x=2 \sin x \cos x$

$\cos 2 x=\cos ^{2} x-\sin ^{2} x$

Substituting these values in eqn 1

$\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)$ -------- eqn 2

We know that,

$\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x$

Applying this in above eqn 2, we get

$\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)$

$\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}$

$\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x$

Therefore,

$\cos 3 x=\cos x-4 \cos x \sin ^{2} x$

Option A is correct

7 0

3 years ago

GI and JL are parallel lines. Which angles are supplementary angles?

solmaris [256]

Answer:

The answer is A.

Step-by-step explanation:

A supplementary angles are angles that when adding both sides will sum up to 180 Degrees.

<JKH and <LKH will be the correct answer because they add up tp 180 degrees.

Star Me!!!

6 0

3 years ago