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Valentin [98]
3 years ago
6

3 tenths +4 tenths +__________tenths

Mathematics
1 answer:
algol [13]3 years ago
6 0

Well four plus seven would equal seven tenths.

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What are the rules to solve a equation with variables on one side​
amm1812

Answer:

3a-10=4+a first subtract a from 3a, this equals 2a-10=4 then add 10 to 4, this equals 2a=14, then divide 14 by 2, the answer is a=7

8 0
3 years ago
Prove the following identity ​
Deffense [45]

Answer:

sec(x)/(tan xsin(x))=cot^2 x+1 = Ture

Step-by-step explanation:

Verify the following identity:

sec(x)/(tan(x) sin(x)) = cot(x)^2 + 1

Hint: | Eliminate the denominator on the left hand side.

Multiply both sides by sin(x) tan(x):

sec(x) = ^?sin(x) tan(x) (cot(x)^2 + 1)

Hint: | Express both sides in terms of sine and cosine.

Write cotangent as cosine/sine, secant as 1/cosine and tangent as sine/cosine:

1/cos(x) = ^?sin(x)/cos(x) sin(x) ((cos(x)/sin(x))^2 + 1)

Hint: | Simplify the right hand side.

((cos(x)/sin(x))^2 + 1) sin(x) (sin(x)/cos(x)) = (((cos(x)^2)/(sin(x)^2) + 1) sin(x)^2)/(cos(x)):

1/cos(x) = ^?(sin(x)^2 (cos(x)^2/sin(x)^2 + 1))/cos(x)

Hint: | Put the fractions in cos(x)^2/sin(x)^2 + 1 over a common denominator.

Put cos(x)^2/sin(x)^2 + 1 over the common denominator sin(x)^2: cos(x)^2/sin(x)^2 + 1 = (cos(x)^2 + sin(x)^2)/sin(x)^2:

1/cos(x) = ^?sin(x)^2/cos(x) (cos(x)^2 + sin(x)^2)/sin(x)^2

Hint: | Cancel down ((cos(x)^2 + sin(x)^2) sin(x)^2)/(sin(x)^2 cos(x)).

Cancel sin(x)^2 from the numerator and denominator. ((cos(x)^2 + sin(x)^2) sin(x)^2)/(sin(x)^2 cos(x)) = (sin(x)^2 (cos(x)^2 + sin(x)^2))/(sin(x)^2 cos(x)) = (cos(x)^2 + sin(x)^2)/cos(x):

1/cos(x) = ^?(cos(x)^2 + sin(x)^2)/cos(x)

Hint: | Eliminate the denominators on both sides.

Multiply both sides by cos(x):

1 = ^?cos(x)^2 + sin(x)^2

Hint: | Use the Pythagorean identity on cos(x)^2 + sin(x)^2.

Substitute cos(x)^2 + sin(x)^2 = 1:

1 = ^?1

Hint: | Come to a conclusion.

The left hand side and right hand side are identical:

Answer: (identity has been verified)

3 0
2 years ago
(-3 1/3, -1 1/3) (1/3,2 1/3) (-1 1/3,3 1/3) (9, -1) (-3,-10) (1 1/3, -1 1/3)Quadrant 1 Quadrant II Quadrant II Quadrant IV
Alchen [17]

Answer:

(-3 1/3, -1 1/3) Quadrant lll

(1/3, 2 1/3) Quadrant l

(-1 1/3, 3 1/3) Quadrant ll

(9, -1) Quadrant lV

(-3,-10) Quadrant lll

(1 1/3, -1 1/3) Quadrant IV

Step-by-step explanation:

Hope this helps! Ask any questions in the comments <3

6 0
3 years ago
If the line joining (3x, x+1) and (11,12) has a slope of 4 what is the value of x​
Irina18 [472]

Answer:

x = 3

Step-by-step explanation:

(3x,\: x +1)=(x_1, \:y_1)

(11,\: 12)=(x_2, \:y_2)

slope =  \frac{y_2 - y_1}{x_2 - x_1} \\  \\ 4 =  \frac{12 - (x + 1)}{11 - 3x}   \\  \\ 4 =  \frac{12 - x  -  1}{11 - 3x}   \\  \\ 4 =  \frac{11 - x}{11 - 3x}   \\  \\ 4(11 - 3x) = 11 - x \\  \\ 44 - 12x = 11 - x \\  \\ 44 - 11 = 12x - x \\  \\ 33 = 11x \\  \\ x =  \frac{33}{11}  \\  \\  \huge \red{ \boxed{x = 3}}

4 0
3 years ago
Which shows the equation y + 2 = 3(x - 2) written in standard form
Law Incorporation [45]

Standard form is ax + by = c.

To change y+2 = 3(x-2) into that form, do:

y+2-2 = 3x -6 -2

-3x + y =  -8

Which is not in the list, so none of the answers are right...

5 0
4 years ago
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