In a class of 200 students, 120 students take german, and 100 study french. if a student must study at least one of these langua
ges, what percent of the students study french but not german
1 answer:
U=200
n(G)=120
n(F)=100
n(GnF)=x
U=n(G)+n(F)-n(GnF)
200=120+100-x
x=20
French but not German is 100-20=80
percentage = 80/200 *100%= 40%
You might be interested in
Answer:
$12
Step-by-step explanation:
It doesn’t show which options?
But the difference would be 2 7/12 or 2.58
2+2=4 because 1+1+1+1 equals and those 2 problems are the same. You got to at least know 1+1+1+1.!
Answer:
1/3 + 3/4 + 4/6 +1/2 =
Step-by-step explanation:
1/6 + 4/6 = 5/6
3/4 + 1/4 = 4/4
5/6 + 4/4 = 9/12
The answer to your question is 2
