The quantity you want is the area under the standard normal curve (with mean 100 and std dev 15) between 110 and 120.
According to my TI-83 calculator,
normalcdf(110,120, 100, 15) = 0.16, or 16%.
If:
Circumference, C = 3 cm
Then:
Radius, r = 0.47746482927569 cm
Diameter, d = 0.95492965855137 cm
Area, A = 0.71619724391353 cm
g(x) = the quantity of x minus one, over four
g(x) = (x-1)/4
g(5) = (5-1)/4
g(5) = 4/4
g(5) = 1
f(x) = x2 − 3x + 3
f(g(5)) =1^2 − 3(1) + 3
f(g(5)) = 1 - 3 + 3
f(g(5)) = 1
Answer:
6 hours
Step-by-step explanation:
40 + 45 = 85
510/85 = 6
