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Scilla [17]
3 years ago
6

QUICK!!!!!!!!!!!!!!!!!!!! What relationships do you notice about the following volumes? 43.75, 32, and 40.5

Mathematics
1 answer:
vovangra [49]3 years ago
8 0

One is that they are all <em>real numbers</em>, or <em>rational numbers</em>.

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Following the lead of the National Wildlife Federation, the Department of the Interior of a South American country began to reco
chubhunter [2.5K]

Answer:

After 2009 the quality of the forests in this country improving.

Step-by-step explanation:

Consider the provided function.

f(t) = \frac{1}{3}t^3-\frac{5}{2}t^2 + 80

f'(t) = t^2-5t

Substitute f'(t)=0.

t^2-5t=0

t(t-5)=0

t=0\ or\ t=5

It is given that  (0 ≤ t ≤ 10)

The test interval are (0,5) and (5,10)

For (0 < t < 5) the value of f'(t)

For (5 < t < 10) the value of f'(t) >0

Hence, the function is increasing from (5,10).

t = 0 corresponds to 2004.

Therefore, after 2009 the quality of the forests in this country improving.

7 0
3 years ago
Change the equation of the parent square root function to represent the equation of the graphed function. Enter the correct answ
Dennis_Churaev [7]

The equation of the parent square root function to represent the equation of the graphed function will be, y=√x-2

According to the statement

we have to show the square root function as a equation in the graphical representation.

So,

we know that the definition of a

Graph a diagram showing the relation between variable quantities, typically of two variables and it also show the relation between more than two variables.

Now, we know that the definition of Equation is a mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.

And the equation obtained from the graph is a y=√x-2 by a some calculations in the graph.

So, The equation of the parent square root function to represent the equation of the graphed function will be, y=√x-2

Learn more about Graph here brainly.com/question/4025726

#SPJ4

7 0
1 year ago
b is the midpoint of AC and E is the midpoint of BD if A(-9,-4) C(-1,6) and E(-4,-3) find the coirdinates of D
natima [27]

To find the coordinate of the point D, we can use the Midpoint point of a line Segment formula. Calculation of the formula are as follows,

Given two points A(x1,y1) and C(x2,y2), we need to locate the midpoint coordinate of this line denoted as B(x,y).

To solve for the value of x and y, we get,

x=(x1+x2)/2 and y=(y1+y2)/2

For the given problem, we need to solve first the midpoint coordinate of AC which is B.

So, A(-9,-4)=A(x1,y1) and C(-1,6)=C(x2,y2)

Hence,

B(x,y)=B((-9+(-1))/2, (-4+6)/2)=B(-10/2,2/2)=B(-5,1)

Now, since the midpoint is given but one point in the line is missing. To solve for the missing point D(x2,y2), we need to use the Midpoint Segment Formula.

 That is, B(-5,1)=B(x,y) and E(-4,-3)=E(x1,y1)

So,

x=(x1+x2)/2 and y=(y1+y2)/2

-5=(-4+x2)/2 and 1=(-3+y2)/2

By Cross Multiplication and Transposing method,

-5(2)=-4+x2 and 1(2)=-3+y2

x2=-10+4=-6 and y2=3+2=5

Thus, the coordinate of D is D(-6,5).

5 0
3 years ago
Lasers can provide highly accurate measurements of small movements. To determine the accuracy of such a laser, it was used to ta
sp2606 [1]

Answer: p-value \approx 0.01

Step-by-step explanation:

Hypothesis testing

\\\left\{\begin{matrix}H_0 : \mu_0 =0\\ H_1: \mu_0 \neq 0\end{matrix}\right.\\

For this problem, we need to use the t-student distribution to  make inference about the data. We calculate the t-statistics as below:

\bar{X} = 20\:\mu m\\S.E. = 60\:\mu m\\n=82\\t_{stat} = \frac{\bar{X}-\mu_0}{S.E/\sqrt{n}}=\frac{20-0}{60/\sqrt{82}}=3.0185

Using a t-statistics table, or using the function TDIST in Microsoft Excel with t_{stat} = 3.0185,\: df (degree\: of\: freedom) = 14 - 1 = 13 with two-tailed distribution, we obtain p-value \approx 0.01.

4 0
3 years ago
What is the midpoint and distance between points P(3,5) and Q(7,5)
storchak [24]

The formula of a midpoint:

M\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points P(3, 5) and Q(7, 5). Substitute:

x=\dfrac{3+7}{2}=\dfrac{10}{2}=5\\\\y=\dfrac{5+5}{2}=\dfrac{10}{2}=5

<h3>M(5, 5)</h3>

d=\sqrt{(5-5)^2+(7-3)^2}=\sqrt{0^2+4^2}=\sqrt{4^2}=4

<h3>Answer:</h3><h3>Midpoint = (5, 5)</h3><h3>Distance = 4</h3>
4 0
3 years ago
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