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fenix001 [56]
3 years ago
5

The interior angles formed by the sides of a pentagon have measures that sum to 540°. What is the measure of angle B?

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
5 0

Answer:

111°

Step-by-step explanation:

I took the assignment.

patriot [66]3 years ago
4 0

Answer:

m∠B = 110°

Step-by-step explanation:

We know that,

The sum of the measures of the angles in a pentagon is 540°.

So, we get,

130 + (x-5) + (x+30) + 75 + (x-35) = 540

i.e. 3x + (130+30+75) - (5+35) = 540

i.e. 3x + 235 - 40 = 540

i.e. 3x + 195 = 540

i.e. 3x = 540 - 195

i.e. 3x = 345

i.e. x= 115°

Now, as m∠B = (x-5)° = (115-5)° = 110°

Hence, the measure of angle B is 110°.

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Step-by-step explanation:

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= > x + \frac{1}{3} = 9



\text{Add} \: - \frac{1}{3} \: \text{ on both sides ,}



= > x + \frac{1}{3} - \frac{1}{3} = 9 - \frac{1}{3} \\ \\ \\ \\ = > x = \frac{(9 \times 3) - 1}{3} \\ \\ \\ \\ = > x = \frac{27 - 1}{3} \\ \\ \\ \boxed{ \bold{= > x = \frac{26}{3} }} \\ \\ \\ or , \boxed{ \bold{ \: x = 8. \bar{6}}}




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Which is the equation of a hyperbola with directrices at x = ±3 and foci at (4, 0) and (−4, 0)?​
Alex Ar [27]

Answer:

\frac{x^2}{12}-\frac{y^2}{4}=1

Step-by-step explanation:

Since our foci are located on the x-axis, then our major axis is going to be the horizontal transverse axis of the hyperbola:

<u>Formula for hyperbola with horizontal transverse axis centered at origin</u>

  • <u />\frac{x^2}{a^2}-\frac{y^2}{b^2}=1
  • Directrices -> x=\pm\frac{a^2}{c}
  • Foci -> (\pm c,0) where a^2+b^2=c^2
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Since we are given our directrices of x=\pm3 and foci of (\pm4,0), then we can set up the directrices equation to solve for a^2:

x=\pm\frac{a^2}{c}\\ \\\pm3=\pm\frac{a^2}{4}\\ \\12=a^2

Now we can determine b^2 to complete our equation for the hyperbola:

a^2+b^2=c^2\\\\12+b^2=4^2\\\\12+b^2=16\\\\b^2=4

Therefore, our equation for our hyperbola is \frac{x^2}{12}-\frac{y^2}{4}=1

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2 years ago
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