The table below represents the velocity of a car as a function of time.

1 answer:

4 0

We plot these data where x corresponds to the time and y corresponds to the velocity. Using the calculator, y - intercept is equal to 50. y-intercept is the y-value when x is zero. The car is accelerating. The average rate of change when x =1 to x=3 is (56-52)/(3-1) or 2 miles/hour^2. The car would reach 60 miles/hour when x=5 from the acceleration of 2. Domain is 5.

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Help!! Can someone explain this to me I’m not getting it.

chubhunter [2.5K]

Answer:

A. 99 sq cm

Step-by-step explanation:

Area of geometric shape

= 2 times the area of one triangle with base a and height c

+ 2 times the area of one triangle with base c and height b

+ Area of rectangle with dimensions a and c.

$= 2 \times \frac{1}{2} ac + 2 \times \frac{1}{2} bc + ac \\ \\ = ac + bc + ac \\ \\ = 2ac + bc \\ \\ = 2(13)(3) + 7(3) \\ \\ = 78 + 21 \\ \\ = 99 \: sq \: cm$

3 0

2 years ago

Read 2 more answers

Ivan sold 31 boxes of oranges on Friday and 29 boxes on Saturday during a citrus sale. There were 10 oranges in each box. How ma

ycow [4]

Answer:

600

Step-by-step explanation:

31 plus 29 is 60

60 x 10 = 600

7 0

3 years ago

For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at

GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

$\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}$ $\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}$

Now, let's add the components of the same direction: