For the square root of a fraction, you could divide the fraction (top divided by the bottom) and then find the square root of the quotient. 9 divided by 16 is 0.5625, and the square root of 0.5625 is 0.75. / / / / For the other way to do it, you have to know that the square root of a fraction is the same thing as the square root of the top over the square root of the bottom. So the sqrt (9/16) = sqrt (9)/sqrt (16) = 3/4. (same thing as 0.75 .)
He can send 600 messages.
40+0.05x=70
-40+0.05x=70-40
0.05x=30
So divide 30 by 0.05
and you get 600.
The graph is missing, so I am using a graph for a similar question.
It migh even be the same question, but the important thing is that I am going to explain you the situation in several sections of this diagram and so you will be able to work this kind of problems by your selfl.
The graph is attached (see the figure).
The graph shows the evolution of the
speed (vertical-axis) over time (horizontal-axis).In the
section A, the speed increases linearly: so the car is
speeding up uniformly (constant acceleration).
In the
section B, the line is horizontal which shows that the speed is constant. That is a
uniform motion.
In the
section C, the speed is decreasing uniformly, so the car is
slowing down with uniform negative acceleration.
So, for this graph, the answer is:
in the setion C. the car is slowing down (uniformly).
Answer:
- 2 - 3i
Step-by-step explanation:
given a complex number a + bi
then the conjugate is a - bi
The real part a remains unchanged while the sign of the imaginary part is reversed.
the conjugate of - 2 + 3i is - 2 - 3i
Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²